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Kitty [74]
3 years ago
11

A 100g sample of a metal was heated to 100oC and then quickly transferred to an insulated container holding 100g of water at 22o

C. The temperature of the water rose to reach a final temperature of 35oC. Which of the following can be concluded?
A) The metal temperature changed more than the water temperature did; therefore the metal
lost more thermal energy than the water gained.
B) The metal temperature changed more than the water temperature did, but the metal lost
the same amount of thermal energy as the water gained.
C) The metal temperature changed more than the water temperature did; therefore the heat
capacity of the metal must be greater than the heat capacity of the water.
D) The final temperature is less than the average starting temperature of the metal and the
water; therefore the total energy of the metal and water decreased.
Chemistry
1 answer:
Lady_Fox [76]3 years ago
4 0

Answer:

B) The metal temperature changed more than the water temperature did, but the metal lost

the same amount of thermal energy as the water gained.

Explanation:

Heat capacity or thermal capacity is defined as the amount of heat required by a given mass of a material to raise its temperature by one unit which means that the heat capacity of the water, that is the quantity of heat required to cause a rise from 22°C to 35°C that is a rise of 13°C is the quantity of heat that caused the drop in temperature of the metal from 100°C to 35°C a change of 65°C

The water has more capacity to absorb heat or a higher heat capacity than the metal

However, the first law of thermodynamics states that energy is neither created nor destroyed, but it changes from one form to another. In this case, the thermal energy lost by the metal is the same as the thermal or heat energy gained by the water

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Answer: a) HCN(aq.)+H_2O\rightleftharoons H_3O^+(aq.)+CN^-(aq.)

b) HCN : acid CN^- :conjugate base.

And, H_2O : base H_3O^+: conjugate acid.

c) HCN(aq.)+NaOH(aq)\rightleftharoons NaCN(aq.)+H_2O(l)

d) NaCN(aq)\rightarrow Na^+(aq.)+CN^-(aq)

e) NaCN(aq)+HCl(aq)\rightarrow NaCl(aq.)+HCN(aq)

Explanation:

a) Weak acid is defined as the acid which does not completely dissociates when dissolved in water. They have high pH. These releases H^+ ions in their aqueous states.

The equation for the dissociation of HCN acid is given by:

HCN(aq.)+H_2O\rightleftharoons H_3O^+(aq.)+CN^-(aq.)

b) According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

For the given chemical equation:

HCN is loosing a proton, thus it is considered as an acid and after losing a proton, it forms CN^- which is a conjugate base.

And, H_2O is gaining a proton, thus it is considered as a base and after gaining a proton, it forms H_3O^+ which is a conjugate acid.

c) Neutralization reaction is a reaction in which an acid reacts with base to produce salt and water.

HCN(aq.)+NaOH(aq)\rightarrow NaCN(aq.)+H_2O(l)

d) The chemical equation for dissociation of NaCN in water.

NaCN(aq)\rightarrow Na^+(aq.)+CN^-(aq)

e) The chemical equation for the reaction of NaCN and HCI

NaCN(aq)+HCl(aq)\rightarrow NaCl(aq.)+HCN(aq)

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Answer:

The relative humidity is low

Explanation:

The higher the dew point rises, the greater the amount of moisture in the air. The lower the humidity, the lower the dew point. The dew point is low and thus water cannot exist in liquid state but as a gas.

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MrMuchimi

Answer: He could add a base to the pool to neutralize the acid.

Explanation:

Chlorine is used to disinfect the pools as it produces hypochlorous acid in water. This hypochlorous acid is unstable and gives hydrochloric acid and nascent oxygen which is used to disinfect.

Cl_2+H_2O\rightarrow HOCl

HOCl\rightarrow HCl+O

The excess acid is neutralized by adding base which produces salt and water and thus decrease the acidity.

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Adding more acid would increase the acidity further.

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Answer:

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