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alukav5142 [94]
3 years ago
7

What is the current scientific thinking about the formation of the solar system?

Chemistry
2 answers:
vitfil [10]3 years ago
8 0

Answer:

D. The solar system formed from the dust and gases in a nebula. A center bulge in the nebula became the sun. The area of flat rings in the nebula became the individual orbital paths in which the planets revolve around the sun in the plane of the ring the path came from. Dust and gas particles found in each area combined to form the planets and their moons.

Explanation:

Stars are born in molecular clouds known as nebula.

According to current most believed theory, solar system was born in solar nebula. It is composed of dust and gases. This cloud of dust and gases collapsed under its own weight and condensed to form the core. It started spiralling and gathering more mass till temperature rose to start the nuclear fusion reaction and the sun was born. The rest of the matter accreted to form planets and their moons. The planets orbit the sun in elliptical paths.

Thus, options D is correct.

Eva8 [605]3 years ago
6 0

The solar system formed dust and many gases in a nebula. The center of the nebula eventually became the sun. The flat rings of outside the nebula became the orbit paths, and that is where the planets stay and rotate around the sun. After that dust particles and gases that were found were all combined up to create planets and moons. so its D

<em>                                    MARK AS BRAINLIEST</em>

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Given: N2 + 3Cl2 → 2NCl3, ΔH = 464 kJ/mol Use the given bond energies and the periodic table to calculate the energy change in t
guapka [62]

The given chemical reaction is:

N_{2}+3Cl_{2}-->2NCl_{3}

ΔH^{0}_{reaction}=∑BE(reactants)-∑BE(products)

                 = {(941 kJ/mol) + (3 * 242 kJ/mol)} -[{2*(3*200 kJ/mol)}]

                     = 467 kJ/mol

Calculating the change in heat when 85.3 g chlorine reacts in the above reaction:

Moles of chlorine = 85.3 g Cl_{2}* \frac{1 mol Cl_{2}} {70.91 g Cl_{2}  }

                             = 1.20 mol Cl_{2}

Heat change when 1.20 mol chlorine reacts

                             = 1.20 mol * \frac{467kJ}{mol} =560.4 kJ

6 0
3 years ago
A brass metal bar is made up of copper and zinc. (Between 50% to 70% is copper.) A brass metal bar weighs 20.15 ounces. 35% of t
dexar [7]

Answer:

The correct answer would be - 13.0975 ounces.

Explanation:

We know that brass is made up of zinc and copper. The copper part of the brass is approximately around 50 to 70% and the remaining is the zinc part.

Given:

Zinc percentage in a brass = 35%

copper percentage would be - 65% (100 - 35 = 65)

Weight of the brass metal bar = 20.15 ounce

ounces of copper are in the bar = ?

Solution:

The weight of the copper in the brass metal in ounces-

= weight of brass* percentage of copper/100

= 20.15*65/100

= 13.0975 ounces of copper.

2nd method =

The weight of the zinc in the brass metal in ounces-

= weight of brass* percentage of zinc/100

= 20.15*35/100

= 7.0525

The weight of the copper = total weight - weight of zinc

= 13.0975 ounces of copper.

6 0
3 years ago
Which of the following answers below is the correctly balanced half-reaction for the reduction of the SO4 ^-2 ion in acid soluti
Rom4ik [11]

Answer:

C

Explanation:

The oxidation number of Sulphur in SO4^2- is;

x + 4(-2) = -2

x - 8 = -2

x = -2 + 8

x = 6

Now,

the oxidation number of sulphur in H2SO3 is

2 (1) + x + 3(-2) = 0

2 + x -6 = 0

-4 + x = 0

x = 4

Hence, the oxidation number of sulphur changed from +6 to +4 which signifies  gain of two electrons as shown in option C.

8 0
3 years ago
A sealed 5.00L flask contains an unknown gas at 1.05 atm and 296 K. How many moles of the unknown gas are in the flask?
xeze [42]

Moles of the unknown gas in the flask : 0.216

<h3>Further explanation</h3>

The gas equation can be written  

\large {\boxed {\bold {PV = nRT}}}

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

V=5 L

P = 1.05 atm

T = 296 K

\tt n=\dfrac{PV}{RT}\\\\n=\dfrac{1.05\times 5}{0.082\times 296}\\\\n=0.216

8 0
3 years ago
What were the first 5 planets that were observed? Why were those the only ones? Help pls!
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Mercury Venus mars Jupiter Saturn
4 0
3 years ago
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