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svetlana [45]
3 years ago
12

The most common experimental technique to perform elemental analysis is combustion analysis, where a sample is burned in a large

excess of oxygen and the combustion products are trapped in a variety of ways. A 99.99% pure, 0.4986 g sample containing only carbon, hydrogen, and nitrogen is subjected to combustion analysis, resulting in the formation of1.423 g CO2, 0.3377 g H2O, and 0.1606 g NO. What is the empirical formula of the sample?
Chemistry
1 answer:
Maurinko [17]3 years ago
5 0

Answer:

C₈H₇N

Explanation:

This problem is solved by calculating the moles of atoms of C, H, N present in the sample and then find their proportions in whole numbers.

MW CO2 = 44 g/mol ⇒ mol CO2 = 4.23 g/ 44 g/mol = 0.096

MW H2O = 18 g/mol  ⇒ mol H2O = 0.3377 g/ 18 g/mol =0.019

MW NO = 30 g/mol ⇒  mol NO = 0.1606 g/ 30 g/mol = 0.054

In terms of mol of atoms of C, H , and N :

0.096: 0.038 : 0.054    (H is 0.38 because there are 2 H per molecule H₂O)

Dividing by the smallest 0.054

7.8 :7 : 1  rounding   8:7:1

empirical formula = C₈H₇N

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A solution contains 72.0 g of HCI and 468 g of (C6H6). what is the mole fraction of benzene
erica [24]
<span>Molar mass (MM) of benzene C6H6
C = 6 * 12 = 72u
H = 6 * 1 = 6u
MM C6H6 = 72 + 6 = 78 g / mol
Benzene - Molar Mass = 78 g --------- 1 mol
Of A Mix has 468 g -------------- x

78x = 468
X = 468/78
X = 6 moles
 
Molar mass (MM) of Hydrochloric Acid HCl H = 1 * 1 = 1u
CI = 1 * 35 = 35u
MM HCl = 1 + 35 = 36 g / mol
 
Hydrochloric Acid - Molar Mass = 36 g ---------- 1 mol
Of A Mix has 72 g ------------ y

36y = 72
Y = 72/36
Y = 2 moles
 
Thus, a mixture has a total of 8 moles (6 mol + 2 mol).
Dividing One Mole Amount of Each Substance by the Number of Total Mole Amounts, Then we will obtain a Molar Fraction of Each:
Molar fraction make benzene = (6/8) simplify 2 = 3/4
Molar Fraction to make Hydrochloric Acid = (2/8) = simplify 2 = 1/4

Note:. The sum of the molar fractions of the always give goes 1, we have: 3/4 + 1/4 = 1
 

ANSWER: 
</span>\boxed{\frac{3}{4}}
4 0
3 years ago
Please match the correct type of reaction to its name.
HACTEHA [7]
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4. Combustion reaction

5. Single replacement reaction
4 0
3 years ago
What is reduction potential?​
Shtirlitz [24]

Answer:

A reduction potential measures the tendency of a molecule to be reduced by taking up new electrons. ... Standard reduction potentials can be useful in determining the directionality of a reaction. The reduction potential of a given species can be considered to be the negative of the oxidation potential.

Explanation:

8 0
3 years ago
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A reaction was performed in which 4.0 g of cyclohexanol was reacted with an acid catalyst to obtain 2.8 g of cyclohexene. calcul
ioda

Answer:

              %age Yield  =  85.36 %

Solution:

The Balance Chemical Reaction is as follow,

               C₆H₁₂O  +   Acid Catalyst    →    C₆H₁₀  +  Acid Catalyst + H₂O

According to Equation ,

              100 g (1 mole) C₆H₁₂O produces  =  82 g (1 moles) of C₆H₁₀

So,

                       4.0 g of C₆H₁₂O will produce  =  X g of C₆H₁₀

Solving for X,

                      X =  (4.0 g × 82 g) ÷ 100 g

                      X  =  3.28 g of C₆H₁₀   (Theoretical Yield)

As we know,

                     %age Yield  =  (Actual Yield ÷ Theoretical Yield) × 100

                     %age Yield  =  (2.8 g ÷ 3.28 g) × 100

                     %age Yield  =  85.36 %

5 0
3 years ago
If the concentration of sugar in water is determined to be 45 g/100 ml and 135 g of sugar was used to make the solution how much
-BARSIC- [3]

Answer:

300g of water was used to make the solution

Explanation:

In the sugar solution, there are dissolved 45g of sugar in 100mL of water. The conversion factor is <em>45g Sugar = 100mL water</em>. That means when 135g of sugar are used the amount of water is:

135g sugar * (100mL water / 45g sugar) =

<h3>300g of water was used to make the solution</h3>
6 0
3 years ago
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