Question 4 (5 points) Which parasite can live in refrigerated conditions?

In terms of energy, how would you classify the following chemical reaction? 2Cu + O2 + 315kJ → 2CuO A. endothermic B. exothermic

ruslelena [56]

By looking at the reaction, we can see that the reactants must absorb 315kJ of energy in order to form the reactants. This means that the reaction is absorbing energy, which would make it A. endothermic.

Hope this helps!

4 0

4 years ago

Read 2 more answers

What is a concave structure

Bess [88]

A concave surface, structure, or line. tr.v. con·caved, concaving, con·caves.
hope that helped

6 0

3 years ago

4. A 0.100 M solution of NaOH is used to titrate an HCl solution of unknown concentration. To neutralize the solution, an averag

PtichkaEL [24]

Answer:

C. 0.191 M

Explanation:

Our goal for this question, is to calculate the concentration of the HCl solution. For this, in the experiment, a solution of NaOH was used to find the moles of HCl. Therefore, our first step is to know the reaction between HCl and NaOH:

$HCl~+~NaOH~->~NaCl~+~H_2O$

The "titrant" in this case is the NaOH solution. If we know the concentration of NaOH (0.100M) and the volume of NaOH (38.2 mL=0.0382 L), we can calculate the moles using the molarity equation:

$M=\frac{mol}{L}$

$0.100~M=\frac{mol}{0.0382~L}$

$mol=0.100~M*0.0382~L=0.0382~mol~of~NaOH$

Now, in the reaction, we have a 1:1 molar ratio between HCl and NaOH (1 mol of HCl is consumed for each mole of NaOH added). Therefore we will have the same amount of moles of HCl in the solution:

$0.0382~mol~of~NaOH\frac{1~mol~HCl}{1~mol~NaOH}=0.0382~mol~HCl$

If we want to calculate the molarity of the HCl solution we have to divide by the litters of HCl used in the experiment (20 mL= 0.02 L):

$\frac{0.0382~mol~HCl}{0.02~L}~=~0.191~M$

The concentration of the HCl solution is 0.191 M

I hope it helps!

8 0

3 years ago

PLEASE ANSWER AS SOON AS POSSIBLE!

timofeeve [1]

? is their a picture if it is please send it

7 0

3 years ago

Amines suitable for preparing buffers are often synthesized by treating ammonia with epoxides. Consider the following series of

Lerok [7]

It is correct to state that Amines are suitable for preparing buffers are often synthesized by treating ammonia with epoxides. The relative structures of compound B are attached accordingly.

<h3>What is an Amine?</h3>

Amine is a family of basic chemical compounds formed by replacing hydrogen with one or more monovalent hydrocarbon radicals.

Apart from medications and pharmaceuticals, amines are employed in the production of azo-dyes and nylon.

They are commonly employed in the development of crop protection, pharmaceutical, and water purification chemicals. They are also used in personal care products.

Ethanol amines are the most widely utilized form of amine on the global market.

It should be noted that ammonia attacks epoxides at the least substituted carbon to produce (A.)

The generated product is then made to react with another epoxide, resulting in the synthesis of successive products.

Learn more about Amines at;
brainly.com/question/17278249
#SPJ1

6 0

2 years ago