Answer : The oxidizing element is N and reducing element is O.
is act as an oxidizing agent as well as reducing agent.
Explanation :
An Oxidizing agent is the agent which has ability to oxidize other or a higher in oxidation number.
Reducing agent is the agent which has ability to reduce other or lower in oxidation number.
The given reaction is :
act as an oxidizing agent.
The oxidation number of N in is calculated as:
(+1)+(x)+3(-2) = 0
x = +5
And the oxidation number of N in 
is calculated as:
(+1)+(x)+2(-2) = 0
x = +3
From the oxidation number method, we conclude that the oxidation number reduced this means itself get reduced to and it can act as an oxidizing agent.
act as a reducing agent.
The oxidation number of O in is calculated as:
(+1)+(+5)+3(x) = 0
x = -2
The oxidation number of O in 
is Zero (o).
Now, we conclude that the oxidation number increases this means itself get oxidized to and it can act as reducing agent.
Answer:
Ionic bonds are stronger than covalent bonds
Answer:
a), b), c) & f)
Explanation:
d) does not apply because Ms value can be either +½ or -½
e) does not apply because Ml - values range from -l to +l, hence l= 2 doesn't exist when l= 1
Answer:
1.66×10^-15
Explanation:
the explanation is in the picture
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0.80M = x/1.5L
x = 1.2 moles
1.2 moles of Na is about 27.6 grams of Na
