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nekit [7.7K]
2 years ago
11

Hypernatremia due to excess water loss: A. Diabetes insipidus B. Dialysis fluid excess C. Hyperaldosteronism D. Older persons​

Chemistry
2 answers:
alex41 [277]2 years ago
5 0

Answer:

Hypernantremia due to excess water loss

  • A. Diabetes insipidus

A rare disorder that causes the body to make too much urine

#Brainly

-Levi

nikdorinn [45]2 years ago
4 0

Answer:

Hypernantremia due to excess water loss A. Diabetes insipidus

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Explanation:

Matter is anything that has volume and/or mass.

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A 0.43g samle of KHP required 24.11cm of NaOH for neutralization. Calculate the molarity of NaOH
expeople1 [14]

Answer:

0.083 M

Explanation:

We'll begin by calculating the number of mole in 0.43 g of KHP (potassium hydrogen phthalate, C₈H₅O₄K). This is can be obtained as follow:

Mass of C₈H₅O₄K = 0.43 g

Molar mass of C₈H₅O₄K = (8×12) + (5×1) + (16× 4) + 39

= 96 + 5 + 64 + 39 = 204 g/mol

Mole of C₈H₅O₄K =?

Mole = mass / molar mass

Mole of C₈H₅O₄K = 0.43 / 204

Mole of C₈H₅O₄K = 0.002 mole

Next, we shall determine the number of mole of NaOH required to react with 0.43 g (i.e 0.002 mole) of KHP. This can be obtained as follow:

C₈H₅O₄K + NaOH → C₈H₄O₄KNa + H₂O

From the balanced equation above,

1 mole of KHP reacted with 1 mole of NaOH.

Therefore, 0.002 mole of KHP will also react with 0.002 mole of NaOH.

Next, we shall convert 24.11 cm³ to L. This can be obtained as follow:

1000 cm³ = 1 L

Therefore,

24.11 cm³ = 24.11 cm³ × 1 L / 1000 cm³

24.11 cm³ = 0.02411 L

Finally, we shall determine the molarity of NaOH. This can be obtained as follow:

Mole of NaOH = 0.00 2 mole

Volume = 0.02411 L

Molarity of NaOH =?

Molarity = mole /Volume

Molarity of NaOH = 0.002 / 0.02411

Molarity of NaOH = 0.083 M

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3 years ago
Which is an advantage of biomass energy?
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If 7.25g of chlorine is reacted with excess hydrogen and produces 7.25 g HCl. What is the percent yield?
lozanna [386]

Answer:

94.61 %

Explanation:

percent yield = (actual yield / theoretical yield) X 100%

The balanced equation for the reaction is:

H2 (g ) + Cl2(g) => 2 HCl (l)

So, the theoretical yield =  

 7.25g of chlorine X (2mol of Cl / 35.453 g of Cl) X (2mol Cl / 2mol of HCl) X  37.469g of Hcl / 2mol of Hcl = 0.409 x 18.735 = 7.663g of Hcl

Using this theoretical yield and the provided value for actual yield, the percent yield = (actual yield / theoretical yield) X 100%

= (7.25 g / 7.663g) X 100

= 94.61 %

   

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3 years ago
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