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AlladinOne [14]
3 years ago
14

Calculate the molar mass for each of the following:

Chemistry
1 answer:
Mila [183]3 years ago
3 0

Answer: a . 152g/mol  b. 102g/mol c. 183g/mol

Explanation:

By stating the atomic masses of each element in the questions, we have;

Fe= 56, S= 32, O= 16, Al = 27, C = 12, H =1 , N = 14, therefore

(a). FeSO4 =  56 + 32 + (16 x 4) =  152g/mol

(b). Al2O3 =  (27 x 2) + (16 x 3) = 102g/mol

(c). C7H5NO3S ( Saccharin, an artificial Sweetner) =

   (12 x 7) + (1 x 5) + 14 + (16 x 3) + 32 =  183g/mol

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Water is poured into a conical container at the rate of 10 cm3/sec. The cone points directly down, and it has a height of 20 cm
8090 [49]

Answer:

\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{2}

Explanation:

Hello,

The suitable differential equation for this case is:

\frac{dV}{dt}=10\frac{cm^3}{s}

As we're looking for the change in height with respect to the time, we need a relationship to achieve such as:

\frac{dh}{dt} = ?*\frac{dV}{dt}

Of course, ?=\frac{dh}{dV}.

Now, since the volume of a cone is V=\pi r^2h/3 and the ratio r/h=15/20=3/4 or r=3/4h, the volume becomes:

V=\pi (\frac{3}{4} h)^2h/3= \frac{3}{16}\pi h^3

We proceed to its differentiation:

\frac{dV}{dh} =\frac{9}{16} \pi h^2\\\frac{dh}{dV} =\frac{16}{9 \pi h^2}

Then, we compute \frac{dh}{dt}

\frac{dh}{dt} = \frac{16}{9 \pi h^2}*\frac{dV}{dt}\\\frac{dh}{dt} = \frac{16}{9\pi h^2}*10\frac{cm^3}{s} =\frac{160}{9 \pi h^2}

Finally, at h=2:

\frac{dh}{dt}_{h=2cm} =\frac{160}{9\pi 2^2}\\\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{s}

Best regards.

4 0
3 years ago
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