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Talja [164]
2 years ago
10

Which kind of intermolecular force attracts the stearate ion to the oil drop?

Physics
1 answer:
Alchen [17]2 years ago
5 0

The intermolecular force attracts of the stearate ion in the oil drop.

<u>Explanation:</u>

  • Dispersion force is the intermolecular force that attracts the stearate ion to the oil drop. The weak force with temporary dipoles. This force is referred to as induced dipole attraction.
  • The Dispersion is meant as an electron in two atoms occupies the position and this force is called induced dipole attraction.
  • The Dispersion force depends on the atomic and molecular weight of the material.  
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At what time was the person at a position of 0m?
Anni [7]

Answer: The person was not at a position of "0" at any time. The person started at 10 metres from the starting line. The explanation below shows how to use the standard formula for position when the initial position is not "0". It is noteworthy that the standard expression of the formula for distance travelled does not include a variable (e.g. "d") for distance at the start (when t(time) = 0)

Explanation: At time = 0, the start, the person was at 10m distance from the starting line. Therefore, to use the standard equation, "s + ut + 1/2att (t squared, that is), distance from starting line = 10 + s, that is, total distance from starting line  equals initial position, 10 metres, plus "s" (distance travelled from t = 0 to t = 1) in metres.

for the section of the graph from "0" seconds (t = 0) to 1 second (t = 1):

s = ut + 1/2att

the initial position is 10 metres.

s = 10

the distance is constant from t = 0 to t = 1, therefore the velocity for the whole of that section of graph must be 0.

u = 0

there is no change in the velocity from t = 0 to t= 1, therefore the acceleration for the first section of the graph must be 0.

a = 0

s = ut + 1/2att

  = (0 x 1) + 1/2 (0 x 1 x 1)

  = (0) + 1/2 (0)

  = 0

total distance from starting line (position) equals initial position plus change in position (distance travelled).

at t = 1,

position = 10 + 0

 = 10 metres

The whole of the graph can be analysed using this process for each straight section of the graph separately, adding "s" for each section to the previous total of distance from starting line.

using "d" for initial distance from starting line ( position ), d1 for distance from starting line at t = 1, d2 for distance from starting line at t = 2, etcetera:

section 1, t = 0 to t = 1:

d1 (t=0 to t=1)  =  10 + s (t=0 to t=1).

section 2, t= 1 to t = 2:

d2 (t=0 to t=2) = 10 + s (t=0 to t=1) + s (t=1 to t=2).

etcetera.

8 0
2 years ago
Sarah observed that different kinds and amounts of fossils were present in a cliff behind her house. She wondered if changes in
MAXImum [283]
This is the answer: Fossil's found in Susan's yard are from prehistoric times.
6 0
3 years ago
A sphere of volume 1.20×10−3m3 hangs from a cable. When the sphere is completely submerged in water, the tension in the cable is
KATRIN_1 [288]

Answer:

B = 62.9 N

Explanation:

This is an exercise on Archimedes' principle, where the thrust force equals the weight of the  liquid

         B = ρ g V

write the equilibrium equation

         T + B -W = 0

         B = W- T               (1)

use the density to write the weight

         ρ = m / V

        m = ρ V

         W = ρ g V

substitute in  1

         B = m g -T

         B = \rho_{body} g V - T

To finish the calculation, the density of the material must be known, suppose it is steel  \rho_{body} = 7850 kg / m³

calculate

         B = 7850 9.8 1.20 10⁻³ - 29.4

          B = 92.3 - 29.4

          B = 62.9 N

4 0
2 years ago
If the radio waves transmitted by a radio station have a frequency of 76.5 mhz, what is the wavelength of the waves, in meters?
____ [38]
Given: Velocity of light    c = 3.00 x 10⁸ m/s

Frequency f = 7.65 x 10⁷/s

Required: Wavelength λ = ?

Formula:  λ = c/f

λ = 3.00 x 10⁸ m/s/7.65 x 10⁷/s

λ = 3.92 m
3 0
2 years ago
A toy car moves 8 min 4 s at the constant velocity. What is the car's velocity?
Schach [20]

Explanation:

<u>Formula:</u>

velocity = (d \div t)

<u>d = distance given</u>

<u>t</u><u> </u><u>=</u><u> </u><u>the amount of time </u><u>given</u>

<u>Substitute the given values into the formula for velocity</u><u>:</u>

v = 8 \div 4

velocity is shortened for v.

8 (distance) divided by 4 (time) equals the velocity.

<u>Solve:</u>

2 = 8 \div 4

The velocity of the toy car equals: B. 2 m/s.

6 0
2 years ago
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