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Talja [164]
3 years ago
10

Which kind of intermolecular force attracts the stearate ion to the oil drop?

Physics
1 answer:
Alchen [17]3 years ago
5 0

The intermolecular force attracts of the stearate ion in the oil drop.

<u>Explanation:</u>

  • Dispersion force is the intermolecular force that attracts the stearate ion to the oil drop. The weak force with temporary dipoles. This force is referred to as induced dipole attraction.
  • The Dispersion is meant as an electron in two atoms occupies the position and this force is called induced dipole attraction.
  • The Dispersion force depends on the atomic and molecular weight of the material.  
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Answer:

0.35 kg

Explanation:

8 cm = 0.08 m

For the block to stay balance, the buoyancy force must be the same as gravity that pulls it down.

Let mass of the block be M, then the gravity would be Mg

Let water density be \rho_w = 1000 kg/m^3, the buoyancy force would be the weight of water that is displaced by the submerged block.

For example, when there is no coin, block is h_0 = 0.0312m submerged. The weight of water displaced must be

W_0 = Ah_0\rho_wg = 0.0312A1000g = 31.2Ag

Which is also the weight of block, of Mg

Therefore M = 31.2A.    (1)

As coins are stacked on top of block, h increase, so as weight of water displaced and total weight of block and coins. Now let m be the total weight of coins. The gravity of block and weight must be (M+m)g. And the weight of water displaced is:

W = Ah\rho g = (M + m)g

h = \frac{M}{A\rho} + \frac{m}{A\rho}

Since the linear plot of h vs m has a slope of 0.089 m/kg, we can interpret it as

\frac{1}{A\rho} = 0.089

A = \frac{1}{0.089\rho} = \frac{1}{89} = 0.011 m^2

So from the eq. (1) we can solve for M = 31.2A = 0.35 kg

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3 years ago
Which identifies the energy transformations that take place in Anna’s body as this process takes place?
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Answer:

Chemical energy is converted to thermal energy and electrical energy.

Explanation:

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Answer:

Q = 5.75 C

Explanation:

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so we have

E_{net} = 2E

E_{net} = \frac{\sigma}{\epsilon_0}

9.00 \times 10^{11} = \frac{Q}{A\epsilon_0}

now we have

Q = 9.00 \times 10^{11}(0.85 \times 0.85)(8.85 \times 10^{-12})

Q = 5.75 C

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4 years ago
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a

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