Answer: 25.5°C
Explanation: take the average of the reading i.e (25 + 26)/2= 25.5
Ok so this is what we know :
2KClO3 -> 2KCl + 3O2 (Always check if equation is balanced - in this case it is)
4.26moles
So we know that we have 4.26 moles of oxygen (O2). Now lets look at the ratio between KClO3 and O2.
We see that the ratio is 2:3 meaning that we need 2KClO3 in order to produce 3O2.
Therefore divide 4.26 by 3 and then multiply by 2.
4.26/3 = 1.42
1.42 * 2 = 2.84
Now we know that the molarity of KClO3 is 2.84 moles.
Multiply by R.M.M to find how many grams of KClO3 we have.
R.M.M of KClO3
K- 39
Cl- 35.5
3O- 3 * 16 -> 48
---------------------------
<span>122.5
</span>2.84 * 122.5 = 347.9 grams therefore the answer is (a)
348 grams needed of KClO3 to produce 4.26 moles of O2.
Hope this helps :).
Answer:
Electron microscopes differ from light microscopes in that they produce an image of a specimen by using a beam of electrons rather than a beam of light. Electrons have much a shorter wavelength than visible light, and this allows electron microscopes to produce higher-resolution images than standard light microscopes.
Explanation:
When,
[OH⁻] = 1.4 × 10⁻³
Then,
pOH = -log (1.4 × 10⁻³)
pOH = 2.85
Also,
pH + pOH = 14
So,
pH = 14 - 2.85
pH = 11.15
As pH is greater than 7, so the solution is Basic in Nature.
Calculating for concentration of [H⁺],
As,
pH = -log [H⁺]
Or,
11.15 = -log [H⁺]
Taking Antilog on both sides,
[H⁺] = 7.07 × 10⁻¹² M
Result:
A solution with a hydroxide ion concentration of 4.15 × 10⁻³<span> M is Basic and has a hydrogen ion concentration of </span><u>7.07 × 10⁻¹² M.</u>