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Answer:
the ion present in the original solution is Ca2+
Explanation:
Precipitation reactions occur when cations and anions in aqueous solution combine to form an insoluble ionic solid called a precipitate.
<u>Step1</u> : If we add Nacl to the solution, there is no precipitate formed
⇒The only possible ion that can form a precipate with Cl- is Ag+; since there is no precipitate formed, Ag+ is not present
<u>Step2</u> : If we add Na2SO4 to the solution, a white precipitate is formed
The possible ions to bind at SO42- are Ca2+ and Fe2+
But the white precipitate formed, points in the direction of Ca2+
⇒This means calcium is present
<u>Step3</u> : If we add Na2CO3 to the filtered solution, there is a precipate formed
Ca2+ will bind also with CO32- and form a precipitate
So the ion present in the original solution is Ca2+
Explanation:
Uranium-238 undergoes a radioactive decay series consisting of 14 separate steps before producing stable lead-206. This series consists of eight α decays and six β decays.
In the process of photosynthesis, when a glucose molecule is formed, THE HEAT CONTENT OF THE REACTION INCREASES, THUS, THE VALUE OF Q IS POSITIVE.
There are two types of chemical reaction, these are exothermic and endothermic reaction. Exothermic reactions are those reactions that gives off heat when they are occurring while endothermic reactions are those reactions that absorb heat from their environment during the course of reaction. Photosynthesis is an endothermic reactions; it absorbs energy from the environment when it is occurring, thus, the heat content of the product is always more than that of the reactants. The heat content of compounds are represented by letter q. For photosynthesis, q is positive, because there is an increase in the heat content of the product [glucose] formed.