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2 years ago

Is the refractive index constant?

2 answers:

8 0

Answer:The refractive index (n?) of a material is defined as the ratio of velocity of light in a vacuum to that in a defined material. The refractive index of a glass is not a constant, but depends on the wavelength of the incident light, known as dispersion

GenaCL600 [577]2 years ago

4 0

Answer: No

Explanation:

The refractive index (n?) of a material is defined as the ratio of velocity of light in a vacuum to that in a defined material. The refractive index of a glass is not a constant, but depends on the wavelength of the incident light, known as dispersion.

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Which item could you use in place of an ammeter to demonstrate that a

love history [14]

Answer:

the answer is D

Explanation:

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2 years ago

True or False: A 24 year old motorcycle driver would not be required to wear protective eyewear when riding in Florida.

n200080 [17]

False people should always wear gear

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2 years ago

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The vapor pressure of ethanol at 293 K is 5.95 kPa and at 336.5 K it is 53.3 kPa. Calculate the enthalpy of vaporization of etha

denis-greek [22]

Answer:

$H=41.3kJmol^{-1}$

Explanation:

The equation relating the the enthalphy, pressure and temperature is expressed as

$ln(\frac{P_{2}}{P_{1}} )=\frac{H}{R}(\frac{1}{T_{1}}-\frac{1}{T_{2}} ) \\$

Where P is the pressure, H is the enthalphy, and T is the temperature.

since the given values are

$T_{1}=293k, \\T_{2}=336.5k\\P_{1}=5.95kPA\\p_{2}=53.3kPA\\and R=8.314J.K^{-1}mol_{-1}$

if we insert values, we arrive at

$ln(\frac{53.3}{5.95} )=\frac{H}{8.314}(\frac{1}{293}-\frac{1}{336.5} )\\2.19=\frac{H}{8.314}(0.00044)\\H=(2.19*8.314)/0.00044\\H=41,268.8Jmol^{-1}\\H=41.3kJmol^{-1}$

4 0

2 years ago

4. Two particles, A and B, are in uniform circular motion about a common center. The acceleration of particle A is 7.3 times tha

HACTEHA [7]

Answer:

Explanation:

Acceleration of particle A is 7.3 times the acceleration of particle B.

Let the acceleration of particle B is a, then the acceleration of particle A is

7.3 a.

Let the period of particle A is T and the period of particle B is 2.5 T.

Let the radius of particle A is RA and the radius of particle B is RB.

Use the formula for the centripetal force

$a=r\omega ^{2}=r\times \frac{4\pi^{2}}{T^{2}}$

So, $r = a\frac{T^{2}}{4\pi^{2}}$

The ratio of radius of A to the radius of B is given by

$\frac{R_{A}}{R_{B}}=\frac{a_{A}\times T_{A}^{2}}{a_{B}\times T_{B}^{2}}$

$\frac{R_{A}}{R_{B}}=\frac{7.3 a\times T^{2}}{a\times 6.25T^{2}}$

RA : RB = 1.17

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2 years ago

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Which ion will act as a weak base in water?

GuDViN [60]

Answer:

An example of a weak base is ammonia. It does not contain hydroxide ions, but it reacts with water to produce ammonium ions and hydroxide ions. The position of equilibrium varies from base to base when a weak base reacts with water. The further to the left it is, the weaker the base.

Explanation:

I hope this helps!!

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2 years ago