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2H₂₍g₎ + O₂ ₍g₎→ 2H₂O
138 mol H₂ × (2 mol H₂O ÷ 2 mol H₂)= 138 mol H₂O
64 mol O₂ × (2 mol H₂O ÷ 1 mol O₂)= 128 mol H₂O
128 mol H₂O
Answer:
0.071 mole
Explanation:
As discovered from Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 molecules.
This simply means that 1 mole of H3PO4 also contains 6.02x10^23 molecules.
If 1 mole H3PO4 contains 6.02x10^23 molecules,
Then, xmol of H3PO4 will contain 4.3x10^22 molecules i.e
Xmol of H3PO4 = 4.3x10^22/6.02x10^23 = 0.071 mole
From the calculations made above, 4.3x10^22 molecules of H3PO4 have 0.071 mole of H3PO4
Answer:
CH
Explanation:
The empirical formular is the simplest formular of a compound. It shows the relative number of elements present in a compounds. It shows the number of atoms of elements present in simple ratios.
In both compounds, the ratio of the carbon to hydrogen s 1:1
In C2H2;
C : H = 2 : 2 (Which is equivalent to 1 : 1)
In C6H6;
C : H = 6 : 6 (Which is equivalent to 1 : 1)
This means the empirical formular is CH
Answer: Carbon Hydrogen and water
1:2:1
Explanation:
Carbohydrates are made of Carbon Hydrogen and water. Hence, they are represented by a general formula Cx(H2O)y.
Carbohydrates have carbon, hydrogen and oxygen in ratio 1:2:1, as is found in glucose (C6H12O6), Glycerose (C3H6O3), Ribose (C5H10O5).
Thus, in all sugars carbon, hydrogen and oxygen are found in ratio 1:2:1