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3 years ago

14

There are no solutions to the system of inequalities shown below.

1 answer:

mixer [17]3 years ago

3 0

Answer:

False, there are actually infinite solutions as these are parallel lines.

Step-by-step explanation:

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What is the remainder when f(x) is divided by x-2 given that f(x)=4x^3-2x^2+x-13?

Ratling [72]

Answer:

13

Step-by-step explanation:

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3 years ago

Pleaseee helppp with thissss asapppp

Natasha2012 [34]

As we know that the standard equation of circle is ${\bf{(x-h)^{2}+(y-k)^{2}=r^{2}}}$ , where <em>r</em> is the radius of circle and centre at <em>(h,k) </em>

Now , as the circle passes through <em>(2,9)</em> so it must satisfy the above equation after putting the values of <em>h</em> and <em>k</em> respectively

${:\implies \quad \sf \{2-(-1)\}^{2}+(9-5)^{2}=r^{2}}$

${:\implies \quad \sf (3)^{2}+(4)^{2}=r^{2}}$

${:\implies \quad \sf 9+16=r^{2}}$

After raising ½ power to both sides , we will get <em>r = +5 , -5</em> , but as radius can never be -<em>ve</em> . So <em>r = +</em><em>5</em><em> </em>

Now , putting values in our standard equation ;

${:\implies \quad \sf \{x-(-1)\}^{2}+(y-5)^{2}=(5)^{2}}$

${:\implies \quad \bf \therefore \quad \underline{\underline{(x+1)^{2}+(y-5)^{2}=25}}}$

<em>This is the required equation of </em><em>Circle</em>

Refer to the attachment as well !

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2 years ago

Given f(x)=8x+13 and g(x)=x^2-5x, find (f-g)x

uysha [10]

(f-g)x= -x²+13x+13

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3 years ago

Write 1 1/3 as a percent

Assoli18 [71]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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