1 mol N₂ - 2 mol NH₃
6 mol N₂ - x mol NH₃
x=2×6/1=12 mol
12 mol NH₃
Answer: :))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))))
Explanation:
Answer:
Approximately 
(note that 
.)
Explanation:
The molarity of a solution gives the number of moles of solute in each unit volume of the solution. In this 
solution in water,
Let 
be the number of moles of the solute in the whole solution. Let 
represent the volume of that solution. The formula for the molarity 
of that solution is:
.
In this question, the volume of the solution is known to be 
. That's 
in standard units. What needs to be found is , the number of moles of in that solution.
The molar mass (formula mass) of a compound gives the mass of each mole of units of this compound. For example, the molar mass of is 
means that the mass of one mole of
.
For this question,
.
Calculate the molarity of this solution:
.
Note that 
(one mole per liter solution) is the same as 
.
Answer: B
Oxygen acts as oxidator in the first reaction.
Explanation:
At reactant side:
Mg = 0
At product side:
MgO = 0
but Oxygen (O) = -2
Mg + O = 0
Mg + (-2) = 0
Mg - 2 = 0
Mg = 2
Magnesium is oxidized by OXYGEN from zero to +2
Oxygen acts as oxidator in the first reaction.
Answer:
Option 1. NO
Explanation:
The balanced equation for the reaction is given below below:
4NH₃ + 6NO —> 5N₂ + 6H₂O
From the balanced equation above,
4 moles of NH₃ reacted with 6 moles of NO.
Finally, we shall determine the limiting reactant. This can be obtained as follow:
From the balanced equation above,
4 moles of NH₃ reacted with 6 moles of NO.
Therefore, 1.24 moles of NH₃ will react with = (1.24 × 6)/4 = 1.86 moles of NO
From the calculation made above, we can see that a higher amount of NO (i.e 1.86 moles) than what was given (i.e 1.79 moles) is needed to react completely with 1.24 moles of NH₃.
Therefore, NO is the limiting reactant and NH₃ is the excess reactant.
Thus, the 1st option gives the correct answer to the question
