Question

Consider the reaction below: 3 h2(g) + n2(g) ? 2 nh3(g) if there are 6 mol of nitrogen (n2) and more than enough hydrogen (h2), how much ammonia (nh3) can be made?

Answer 1

1 mol N₂ - 2 mol NH₃
6 mol N₂ - x mol NH₃

x=2×6/1=12 mol

12 mol NH₃