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laila [671]
3 years ago
12

Please help me:( I need help with this question

Physics
1 answer:
VladimirAG [237]3 years ago
6 0
Your answer would be B 
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1. On one of the shelves in your physics lab is displayed an antique telescope. A sign underneath the instrument says that the t
Ira Lisetskai [31]

Answer:

a)  f_{e} = 3,375 cm , b)  f₀ = 77.625 cm

Explanation:

The magnification of a telescope is, to see at the far point of vision (infinity image)

        m = - f₀ /  f_{e}

The length of the tube is

        L = f₀ + f_{e}

a) The focal length of the eyepiece

       L = - m  f_{e} +  f_{e}

       L = f_{e} (1-m)

        f_{e} = L / (1-m)

Let's calculate

        f_{e} = 81.0 / (1 - (-23.0)

        f_{e} = 3,375 cm

b) the focal length of the target

       f₀ = -m  f_{e}

       f₀ = 23 (3.68)

       f₀ = 77.625 cm

8 0
3 years ago
A man pushes a lawn mower on a level lawn with a force of 195 N. If 37% of this force is directed downward, how much work is don
densk [106]

Answer:

W = 1032.6 J

Explanation:

Net force by which man push the lawn mower is given as

F = 195 N

now it is given that 37% of this force is vertically downwards

so we will have

F_y = 0.37 \times 195

F_y = 72.15 N

now we also know that

F_x^2 + F_y^2 = F^2

here we have

F_x^2 + 72.15^2 = 195^2

F_x = 181.2 N

Now work done by this force to move the lawn mower is given as

W = F_x . d

W = (181.2)(5.7 m)

W = 1032.6 J

7 0
3 years ago
A 6 kg block initially at rest is pulled to East along a horizontal surface with coefficient of kinetic friction μk=0.15 by a co
ozzi

Answer:

1.8 m/s

Explanation:

Draw a free body diagram of the block.  There are four forces:

Normal force Fn up.

Weight force mg down.

Applied force F to the east.

Friction force Fn μ to the west.

Sum the forces in the y direction:

∑F = ma

Fn − mg = 0

Fn = mg

Sum the forces in the x direction:

F − Fn μ = ma

F − mg μ = ma

a = (F − mg μ) / m

a = (12 N − 6 kg × 9.8 m/s² × 0.15) / 6 kg

a = 0.53 m/s²

Given:

Δx = 3 m

v₀ = 0 m/s

a = 0.53 m/s²

Find: v

v² = v₀² + 2aΔx

v² = (0 m/s)² + 2 (0.53 m/s²) (3 m)

v = 1.8 m/s

8 0
3 years ago
Reflection off of a smooth surface like a mirror is an example of diffuse reflection.
Akimi4 [234]

Answer:

true

Explanation:

Reflection is when light bounces off an object. If the surface is smooth and shiny, like glass, water or polished metal, the light will reflect at the same angle as it hit the surface. ... This is called diffuse reflection. Diffuse reflection is when light hits an object and reflects in lots of different directions.

8 0
3 years ago
Read 2 more answers
Calculate the force it would take to accelerate a 250 kg motorcycle at a rate of 5 m/s2
Sphinxa [80]

Force = mass x acceleration

Mass is given to be 250kg

Acceleration is given to be 5m/s^2

Force = 250kg x 5m/s^2 = 1,250 kgm/s^2 = 1,250 Newtons

7 0
3 years ago
Read 2 more answers
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