Answer:
K = [NO₂]⁴[O₂] / [N₂O₅]²
Explanation:
Based on the chemical equilibrium reaction:
2 N₂O₅(g) ⇄ 4NO₂(g) + O₂(g)
The equilibrium reaction is obtained as the ratio between the multiplication of the concentrations of the reactants over the products powered to its reaction coefficient. That is:
<h3>K = [NO₂]⁴[O₂] / [N₂O₅]²</h3>
Answer:10.0 mL of 0.00500 M phosphoric acid
Explanation:
If we look at the Ka values of the acids, we will realize that phosphoric acid has a Ka of 7.1 * 10-3. It is the only acid in the list having acid dissociation constant less than 1. This means that it does not ionize easily in solution and a very large volume of base must be added to ensure that it reacts completely. Acids with Ka >1 are generally regarded as strong acids. All the acids listed have Ka>1 except phosphoric acid.
Answer:
ΔG = -8.812 kJ/mol
Explanation:
To obtain the free energy of a reaction you can use the expression:
ΔG = ΔG° + RT ln Q
<em>Where: </em>
<em>ΔG° is Standard Gibbs Free energy: -16.7kJ/mol = -16700J/mol</em>
<em>R is gas constant: 8.314472 J/molK</em>
<em>T is absolute temperature (37°C + 273.15 = 310.15K)</em>
<em>And Q is reaction quotient: 21.3</em>
<em />
Replacing in the formula:
ΔG = ΔG° + RT ln Q
ΔG = -16700J/mol + 8.314472J/molK*310.15K ln 21.3
ΔG = -8812.4J/mol
<h3>ΔG = -8.812 kJ/mol</h3>
<em />
Answer:MnCO3+2H2O----->MnO2+ HCO3-+2e-+3H+
Explanation:The equation to be balanced is
MnCO3 ------> MnO2+HCO3-
The oxidation number of Mn changes from +2 in MnCO3 to +4 in MnO2
Therefore two electrons must be added to the right as shown below:
MnCO3 -------> MnO2+ HCO3-+ 2e-Now,there is one negative charge HCO3- and 1 negative charge on the two electrons making a total of -3 charges on the right. There is zero charge on the left.
To balance the equation,add3H+on the right,to cancel out the charges.
MnCO3 --------> MnO2+HCO3-+2e-+3H+
Adding H2O to balance Hydrogen and Oxygen atoms:
MnCO3+2H2O ------->MnO2+HCO3-+2e-+3H+
