The Group number of a non-transition metal can be used to find the number of valence electrons in an atom of that element. The ones place of the group number is the number of valence electrons in an atom of these elements
Answer:
[N2] = [O2] = 0.841M
And [NO] = 0.00172M
Explanation:
The equilibrium constant of this reaction, Kc, is:
Kc = 2400 = [N2] [O2] / [NO]²
<em>Where [] are the equilibrium concentration of each specie.</em>
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The initial concentration of [N2] = [O2] = 0.850M. The equilibrium will shift to the left in order to produce NO. The equilibrium concentrations are:
[N2] = [O2] = 0.850M - X
And [NO] = 2X
Replacing:
2400 = [0.850-X]² / [2X]²
9600X² = 0.7225 - 1.7 X + X²
0 = 0.7225 - 1.7 X - 9599X²
Solving for X:
X = -0.0088M. False solution, there is no negative concentrations.
X = 0.00859M. Right solution.
Replacing:
[N2] = [O2] = 0.850M - 0.00859M
And [NO] = 2*0.00859M
[N2] = [O2] = 0.841M
And [NO] = 0.00172M
Answer:
a system in chemical nomenclature and notation of indicating the oxidation state of the significant element in a compound or ion by means of a Roman numeral that is used in parentheses after the name or part of the name designating this element and ending invariably in -ate in the case of an anion and that is placed. Stock nomenclature for inorganic compounds is a widely used system of chemical nomenclature developed by the German chemist Alfred Stock and first published in 1919. In the "Stock system", the oxidation states of some or all of the elements in a compound are indicated in parentheses by Roman numerals.
Explanation:
Brainliest please?
The Period Table of Elements has more elements that have been discovered since Mendeleyev's time.
In the modern table the elements are arranged with increasing atomic number. In Mendeleyev's table, they were arranged with increasing atomic weight.
