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levacccp [35]
3 years ago
12

Newton's third law says that for every force there is an equal reaction force in the opposite direction. what does this imply ab

out the force of gravity associated with a person standing on the earth?
Physics
1 answer:
stealth61 [152]3 years ago
7 0

This imply that the force applied by the gravity of the earth on the person, is equal to the force applied by the person on the earth.

According to the Newton's third law, for every force there is an equal reaction force, in the case of person standing on the earth, the gravity of the earth pulls the person by the same magnitude as the force applied by the person on the earth (which is equal to the weight of the person)..

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To develop this problem it is necessary to apply the concepts given in the balance of forces for the tangential force and the centripetal force. An easy way to detail this problem is through a free body diagram that describes the behavior of the body and the forces to which it is subject.

PART A) Normal Force.

F_n = \frac{mv^2}{r}

N+mgcos\theta = \frac{mv^2}{r}

Here,

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a_T = -16.10ft/s^2

Negative symbol indicates deceleration.

<em>NOTE: For the problem, the graph in which the turning radius and the angle of suspension was specified was not supplied. A graphic that matches the description given by the problem is attached.</em>

8 0
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The best and most correct answer among the choices provided by your question is the third choice or number 3.

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I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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A rock from space in Earth's Atmosphere would be considered?
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A meteor mate

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hope this helps

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