To solve this problem we will apply the concepts related to the Magnetic Force, this is given by the product between the current, the body length, the magnetic field and the angle between the force and the magnetic field, mathematically that is,

$F = ILBsin \theta$

Here,

I = Current

L = Length

B = Magnetic Field

$\theta$ = Angle between Force and Magnetic Field

But $\theta = 90\°$

$F = ILB$

Rearranging to find the Magnetic Field,

$B = \frac{F}{IL}$

Here the force per unit length,

$B = \frac{1}{I}\frac{F}{L}$

Replacing with our values,

$B = \frac{0.130N/m}{16.5}$

$B = 0.0078T$

Therefore the magnitude of the magnetic field in the region through which the current passes is 0.0078T

6 0

3 years ago

JUST PLZ HELP!!! Why does the lightbulb in the right electrical circuit turn on but not the one on the left?

makkiz [27]

Because,

In left image pin is not touch to the wire.

In right image pin is touch to the wire.

Hope it helps you.....

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Mark be Brainliest.....

Please.....

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8 0

3 years ago

Read 2 more answers

A resistor is connected to a 36v power supply. An ammeter measures a current of 2.0 A going through it. Determine the resistance

m_a_m_a [10]

R = 18 ohms

Explanation:

Given:

V = 36 volts

I = 2.0 A

R = ?

Use Ohm's law to solve for the resistance:

V = IR

R = V/I

= (36 volts)/(2.0 A)

= 18 ohms

8 0

2 years ago