Answer:
The correct answer is option D.
Explanation:
From the given options the reaction which is not a double replacement reaction is:

This because the above reaction is an example of single replacement reaction.

Whereas;
Double replacement reaction is a type of chemical reaction in which exchange of ions among the reactants take place.

Answer:
The axial force is 
Explanation:
From the question we are told that
The diameter of the shaft steel is 
The length of the cylindrical bushing 
The outer diameter of the cylindrical bushing is 
The diametral interference is 
The coefficient of friction is 
The Young modulus of steel is 
The diametral interference is mathematically represented as

Where
is the pressure (stress) on the two object held together
So making
the subject

Substituting values


Now he axial force required is

Where A is the area which is mathematically evaluated as

So 
Substituting values


Hi!
The answer would be A. Isobaric Process
<h3>Explanation:</h3>
Isobaric process is a process where the pressure inside a system remains unchanged. In the Pressure Volume graph given, you can see that the pressure (y axis) remains constant with an increasing volume ( x axis). An example of this would be heating a container with a movable piston. Now, the degree of pressure is dependent on the frequency of collisions of particles inside a system on the walls. If this frequency changes, the pressure changes (proportionally). In our example, heating a container with a movable piston results in the particles inside the container to gain kinetic energy and move faster, meaning an increased frequency of collisions (higher pressure), but at the system time the increase in pressure results in the piston being pushed outwards, causing the volume of the container to increase. This results in decreased frequency of collision of the particles with the walls of the container (lesser pressure). This results in the a zero net effect on the pressure.
Hope this helps!
Answer:
Explanation:
Average speed = Total distance / Total time.
100 km/hr
r = 100 km / hr
t = 6 hours
d = 6 * 100 = 600 km
120 km / hr
r = 120 km / hr
t = 5 hour
d = 120 * 5
d = 600 km
Total distance = 600 + 600 = 1200 km
Total time = 5 hour + 6 hours = 11 hours.
Average speed = 1200 km / 11 hours = 109.1
The answer to this question would be:3850ft
To answer this question, you need to convert the speed velocity from miles/hour into feet/second. The equation would be: 750 miles/hour x 5280 foot/mile x 1 hour/3600second = 1100 ft/s
Then multiply the time with the velocity= 3.5 second x 1100 ft/s= 3850ft