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levacccp [35]
3 years ago
7

Solve for x. z = 6 π x y

Mathematics
2 answers:
rusak2 [61]3 years ago
3 0
The answer to the question

Advocard [28]3 years ago
3 0

Answer:

The value of the equation for x is x=\frac{z}{6 \pi y} .  

Step-by-step explanation:

Consider the provided equation.

z = 6 \pi x y

We need to solve the above equation for x.

Divide both the sides by 6 \pi y.

\frac{z}{6 \pi y} =\frac{6 \pi x y}{6 \pi y}

x=\frac{z}{6 \pi y}

Hence, the value of the equation for x is x=\frac{z}{6 \pi y} .  

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I need help on this I am just going to use the picture
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Answer:

D

Step-by-step explanation:

let y = f(x), that is

y = \frac{2x-3}{5}

Rearrange making x the subject

Multiply both sides by 5

5y = 2x - 3 ( add 3 to both sides )

5y + 3 = 2x (divide both sides by 2 ) , then

x = \frac{5y+3}{2}

Change y back into term of x, hence

f^{-1}(x) = \frac{5x+3}{2} → D

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3 years ago
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Divede decimals by a whole number in this question 3.9÷3​
IgorC [24]

Answer:

The answer is 1.3, 1 3/10

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If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w
MatroZZZ [7]

Let x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11} be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.

2. If the mean weight of the 7 other players is 202 lb, then

\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.

3. From the previous statements you have that

x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.

Add these two equalities and then divide by 11:

x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.

Answer: the mean weight of the 11-person team is 208\dfrac{10}{11}\ lb.

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Answer:

24/36 = 12 x 2/12 x 3 = 2/3.

Step-by-step explanation:

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