Answer:
Distance, S = 130m
Explanation:
Given the following data;
Initial velocity = 2m/s
Final velocity = 28m/s
Acceleration = 3m/s²
To find the distance, we would use the third equation of motion.
V² = U² + 2aS
Substituting into the equation, we have;
28² = 2² + 2*3*S
784 = 4 + 6S
6S = 784 - 4
6S = 780
S = 780/6
Distance, S = 130m
Answer: 1.62 m
Explanation: In order to solve this problem we have to use the definition of Coulomb force whic is given by:
F=(k*q1*q2)/d^2 where k is a constant 9*10^9 N/C^2*m^2. d is the distance between tha charges q1 and q2.
then we can:
d^2= (k*q1*q2)/F= (9*10^9*30.3*10^-6*68.2*10^-6)/7.09=1.62 m
(note we have considered q2 as positive because we are determining d^2 by using the magnitude of the electric Force bewteen the charges).
Answer:
3.2 seconds
Explanation:
When the cars collide, they have the same position.
x₁ = x₂
-4 + 1.1t = 8.8 − 2.9t
4t = 12.8
t = 3.2
A colloid I think. Don’t hold it against me if I’m wrong my dude.
