Answer:
θ = 4.438 * 10^-18 C / m^2
x = 2.0 m
Explanation:
Given:
V_1 = 420 m/s
Δ r = 2.0 m
m_e = 9.109 *10^-31 kg
q_e = 1.602 * 10^-19 C
ε_o = 8.85 * 10^-12
part a
Energy Principle:
E_k,1 - F_e*Δ r = 0
Electric Field strength of infinite sheet
E = θ / 2*ε_o
0.5*m_e* V_1^2 - E*q_e*Δ r = 0
0.5*m_e* V_1^2 - θ*q_e*Δ r / 2*ε_o = 0
θ = (m_e*ε_o* V_1^2) / q_e*Δ r
θ = (9.109*10^-31*8.85*10^-12* 420^2) / 1.602*10^-12*2
θ = 4.438 * 10^-18 C / m^2
part b
Since the Volt potential is constant of a infinite long uniform charge distribution:
0.5*m_e* V_1^2 - E*q_e*Δ r = 0
r_1 = x
r_2 = 0
0.5*m_e* V_1^2 - θ*q_e*x / 2*ε_o = 0
x = (m_e*ε_o* V_1^2) / q_e*θ
x = (9.109*10^-31*8.85*10^-12* 420^2) / 1.602*10^-12*4.438 * 10^-18
x = 2 . 0 m
Answer:
yes he will get a ticket
Explanation:
because when he applies brake on the distance 2 miles his final velocity is 72.3miles per hour so it is higher than 55mph
Answer: Stars are in space for very long time, much longer than that one night. You are looking back in time because those stars have been there for so long that it’s like looking back in time, to when those stars were there.
Explanation:
May I please have brainlest
Answer:
Final velocity= 84 m/s
Explanation:
V final= V initial + a * t
Vf = 0+ 12 (7)
Vf= 84 m/s
