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GREYUIT [131]
3 years ago
15

Which of these forces could speed up a baseball?

Physics
2 answers:
kkurt [141]3 years ago
5 0
B) Applied and gravitational forces
Slav-nsk [51]3 years ago
5 0

Answer:

b)

Explanation:

You might be interested in
A 3.00 kg mass is traveling at an initial speed of 25.0 m/s. What is the
Nitella [24]

Answer:

The magnitude of the force required to bring the mass to rest is 15 N.

Explanation:

Given;

mass, m = 3 .00 kg

initial speed of the mass, u = 25 m/s

distance traveled by the mass, d = 62.5 m

The acceleration of the mass is given as;

v² = u² + 2ad

at the maximum distance of 62.5 m, the final velocity of the mass = 0

0 = u² + 2ad

-2ad = u²

-a = u²/2d

-a = (25)² / (2 x 62.5)

-a = 5

a = -5 m/s²

the magnitude of the acceleration = 5 m/s²

Apply Newton's second law of motion;

F = ma

F = 3 x 5

F = 15 N

Therefore, the magnitude of the force required to bring the mass to rest is 15 N.

4 0
3 years ago
Which form of the law of conservation of energy describes the motion of the block as it slides on the floor from the bottom of t
aivan3 [116]

Answer:

Explanation:

Let assume begins movement at zero point, that is, height is equal to zero. The block has an initial linear kinetic energy and no gravitational potential energy and end with no linear kinetic energy, some gravitational potential energy and work losses due to slide friction. In mathematical terms, this system can be model as follows:

K_{1} = U_{2} + W_{loss, 1 \longrightarrow 2}

Where K, U, W are linear kinetic energy, gravitational potential energy and work, respectively.

8 0
3 years ago
A particle with charge 3.01 µC on the negative x axis and a second particle with charge 6.02 µC on the positive x axis are each
ra1l [238]

Answer:

The third particle should be at 0.0743 m from the origin on the negative x-axis.

Explanation:

Let's assume that the third charge is on the negative x-axis. So we have:

E_{1}+E_{3}-E_{2}=0

We know that the electric field is:

E=k\frac{q}{r^{2}}

Where:

  • k is the Coulomb constant
  • q is the charge
  • r is the distance from the charge to the point

So, we have:

k\frac{q_{1}}{r_{1}^{2}}+k\frac{q_{3}}{r_{3}^{2}}-k\frac{q_{2}}{r_{2}^{2}}=0

Let's solve it for r(3).

\frac{3.01}{0.0429^{2}}+\frac{9.03}{r_{3}^{2}}-\frac{6.02}{0.0429^{2}}=0

r_{3}=0.0743\:  

Therefore, the third particle should be at 0.0743 m from the origin on the negative x-axis.

I hope it helps you!

 

3 0
3 years ago
Is Air <br> Heterogenous<br> Homogenous<br> suspension <br> compound <br> element
Bumek [7]
Air is heterogeneous.
7 0
4 years ago
How does an atom of chlorine-37 become a chloride ion with a -1 charge?
kirill115 [55]

Answer:

B. The atom gains 1 electron, to make a total of 18 electrons.

Explanation:

Chlorine is the 17th element in the periodic table, so it has atomic number 17:

Z = 17

This means that a neutral atom of chlorine has 17 protons and 17 electrons.

When a chlorine atom gains 1 electron, its electric charge (initially zero) becomes -1, since the electron has negative charge of -1 (in elemntary charge units). This also means that the number of electrons in the ion is now

17 + 1 = 18

So the correct answer is

B. The atom gains 1 electron, to make a total of 18 electrons

5 0
3 years ago
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