Answer:
y=8.1
Step-by-step explanation:
<em>AB</em> + <em>ACB</em> = <em>A</em> (<em>B</em> + <em>CB</em>) = <em>A</em> (<em>I</em> + <em>C </em>) <em>B</em>
Taking the inverse gives
(<em>A</em> (<em>I</em> + <em>C </em>) <em>B</em>)⁻¹ = <em>B </em>⁻¹ (<em>I</em> + <em>C</em> )⁻¹ <em>A</em> ⁻¹
so the answer is (A)
When x is 4 the diagonal line is on the first line above the 4 so that would be y=1
Answer:
5n+3
Step-by-step explanation:
Answer:
See below
Step-by-step explanation:
Vertical velocity will be affected by gravity in this scenario
df = do + vo t + 1/2 a t^2 do = original height = 4 ft a = -32.2 ft/s^2
<u>df = 4 + 89 t - 1/2 (32.2) t^2 df = height</u>
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On the way up and the way down, the ball may reach height of 102.2125 ft :
102.2125 = 4 + 89 t - 1/2 (32.2) t2 re-arrange to:
-16.1 t^2 + 89t - 98.2125 =0
Use Quadratic Formula to find <u>t = 1.5 and 4.0 s </u>