Answer:
D
Explanation:
If it is of very high intensity it will be 85-100%
Answer:
1.2cm
Explanation:
V=(2ev/m)^1/2
=(2*1.6*10^19 x2500/ 1.67*10^27)^1/2
=6.2x10^5m/s
Radius of resulting path= MV/qB
= 1.67*10^-27x6.92*10^6/1.6*10^-16 x0.6
=0.012m
=1.2cm
Answer:
c. ![4.582\times10^{21} kg](https://tex.z-dn.net/?f=4.582%5Ctimes10%5E%7B21%7D%20kg)
Explanation:
= Initial distance between asteroid and rock = 7514 km = 7514000 m
= Final distance between asteroid and rock = 2823 km = 2823000 m
= Initial speed of rock = 136 ms⁻¹
= Final speed of rock = 392 ms⁻¹
= mass of the rock
= mass of the asteroid
Using conservation of energy
Initial Kinetic energy of rock + Initial gravitational potential energy = Final Kinetic energy of rock + Final gravitational potential energy
![(0.5) m v_{i}^{2} - \frac{GMm}{r_{i}} = (0.5) m v_{f}^{2} - \frac{GMm}{r_{f}} \\(0.5) v_{i}^{2} - \frac{GM}{r_{i}} = (0.5) v_{f}^{2} - \frac{GM}{r_{f}} \\(0.5) (136)^{2} - \frac{(6.67\times10^{-11}) M}{(7514000)} = (0.5) (392)^{2} - \frac{(6.67\times10^{-11}) M}{(2823000)} \\M = 4.582\times10^{21} kg](https://tex.z-dn.net/?f=%280.5%29%20m%20v_%7Bi%7D%5E%7B2%7D%20-%20%5Cfrac%7BGMm%7D%7Br_%7Bi%7D%7D%20%3D%20%280.5%29%20m%20v_%7Bf%7D%5E%7B2%7D%20-%20%5Cfrac%7BGMm%7D%7Br_%7Bf%7D%7D%20%5C%5C%280.5%29%20v_%7Bi%7D%5E%7B2%7D%20-%20%5Cfrac%7BGM%7D%7Br_%7Bi%7D%7D%20%3D%20%280.5%29%20v_%7Bf%7D%5E%7B2%7D%20-%20%5Cfrac%7BGM%7D%7Br_%7Bf%7D%7D%20%5C%5C%280.5%29%20%28136%29%5E%7B2%7D%20-%20%5Cfrac%7B%286.67%5Ctimes10%5E%7B-11%7D%29%20M%7D%7B%287514000%29%7D%20%3D%20%280.5%29%20%28392%29%5E%7B2%7D%20-%20%5Cfrac%7B%286.67%5Ctimes10%5E%7B-11%7D%29%20M%7D%7B%282823000%29%7D%20%5C%5CM%20%3D%204.582%5Ctimes10%5E%7B21%7D%20kg)
Answer: a
Explanation: The color of a star is linked to its surface temperature. The hotter the star, the shorter the wavelength of light it will emit. The hottest ones are blue or blue-white, which are shorter wavelengths of light. Cooler ones are red or red-brown, which are longer wavelengths.
I think the answer is CuF2