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3 years ago

What is night vision pls explain in long answer you can copy from google

Physics

1 answer:

olasank [31]3 years ago

4 0

Answer:

Night vision is the ability to see in low-light conditions. Whether by biological or technological means, night vision is made possible by a combination of two approaches: sufficient spectral range, and sufficient intensity range.

Explanation:

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a runner covers the last straigjt stretch of a race in 4 s. during that time, he speeds up from 5m/s to 9m/s.

PtichkaEL [24]

During that final period of time,
his acceleration is
(9 m/s - 5 m/s) / (4 sec) = 1 m/s² .

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3 years ago

A ball falls off of a 3m tall shelf. How long will it take for the

natali 33 [55]

Answer:

0.8s

Explanation:

Given parameters:

Height of shelf = 3m

Unknown:

Time it will take to hit the ground = ?

Solution:

To solve this problem, we use the expression below;

x = ut + $\frac{1}{2}$ gt²

x is the height

u is the initial velocity = 0m/s

g is the acceleration due to gravity = 9.8m/s²

t is the time taken = ?

Now insert the parameters and solve for t;

3 = (0 x t) +( $\frac{1}{2}$ x 9.8 x t²)

3 = 4.9t²

t² = 0.6

t = 0.8s

7 0

3 years ago

What describes a sound wave as it travels through a medium

Softa [21]

Sound waves in air (and any fluid medium) are longitudinal waves because particles of the medium through which the sound is transported vibrate parallel to the direction that the sound wave moves.

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3 years ago

When drawing ray diagrams involving thin lenses, how many rays (at a minimum) are needed show the image distance and magnificati

Rufina [12.5K]

Answer:

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3 years ago

Two capacitors of capacitances 25 µF and 50 µF are connected in series with a 33-V battery. How much energy is stored in the 25-

torisob [31]

Answer:

6.05×10⁻³ J

Explanation:

Note: Two capacitors connected in series behaves like two resistors connected in parallel.

Using

1/Ct = 1/C1+1/C2

Ct = (C1×C2)/(C1+C2)............................ Equation 1

Where Ct = combined capacitance of the two capacitor, C1 = Capacitance of the first capacitor, C2 = capacitance of the second capacitor.

Given: C1 = 25 µF, C2 = 50 µF

Substitute into equation 1

Ct = (25×50)/(25+50)

Ct = 1250/75

Ct = 16.67 µF.

Using

Q = CV.................... Equation 2

Where Q = Charge, V = Voltage.

Given: V = 33 V, C = 16.67 µF = 16.67×10⁻⁶ F

Substitute into equation 2

Q = 33(16.67×10⁻⁶)

Q = 5.5×10⁻⁴ C.

Since both capacitors are connected in series, the same amount of charge flows through them.

Using,

E = 1/2Q²/C.................. Equation 3

Where E = Energy stored in the 25-µF capacitor

Given: Q =5.5×10⁻⁴ C, C = 25 µF = 25×10⁻⁶ F

Substitute into equation 3

E = 1/2(5.5×10⁻⁴)²/ 25×10⁻⁶

E = 6.05×10⁻³ J.

5 0

3 years ago