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allsm [11]
3 years ago
8

What is the kinetic energy of a 1.0-kg billiard ball that moves at 5.0 m/s?

Physics
1 answer:
romanna [79]3 years ago
3 0
K=1/2(mass)(velocity)^2
Mass=1.0
Velocity=5.0
K=1/2(1)(5)^2
K=12.5 J 
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Por favor, necesito ayuda urgente 4. vectores perpendiculares de 25 y 40 unidades cada uno. Hallar gráfica y numericamente el ve
Darina [25.2K]

Answer:

4)  R = 47.17 units , 5)  R= 10,29 unidades, 6)   R= 2994,4 km ,    θ = -33,7

Explanation:

Este es un ejercicio de adición de vectores

4) como los vectores son perpendiculares.

Para encontrar la resultante podemos usar el teorema de pitoras

        R =  √ a² + b²

        R = √√ ( 25² + 40²)

        R =  47,17 unidades

5)  Este caso como el angulo es diferente de 90 debemos usar la relación de pitoras completa

        R² =  a² + b² + 2 a b cos θ

donde el angulo es entre los vectores a y b

        R² = 12² + 16² – 2 12 16 cos 40

        R²= 400 – 294,16

       R= 10,29 unidades

6) En este caso los dos desplazamientos son perpendiculares, por lo cual Usamos el teorema de Pitágoras

          R = √ (2400² + 1600²)

          R= 2994,4 km

para el angulo de este desplazamiento usamos trigonometría

           tan θ = y/x

           θ = tan⁻¹ y/x

           θ = tan⁻¹ 1600/(-2400)

           θ = -33,7  

TRASLATE

This is a vector addition exercise

4) as the vectors are perpendicular.

To find the result we can use the Poreor theorem

        R = √ a² + b²

        R = √ (25² + 40²)

        R = 47.17 units

5) This case, as the angle is different from 90, we must use the complete ratio of the pitoras

        R² = a² + b² + 2 a b cos θ

where the angle is between vectors a and b

        R² = 12² + 16² - 2 12 16 cos 40

         R² = 400 - 294.16

       R = 10.29 units

6) In this case the two displacements are perpendicular, which is why we use the Pythagorean theorem

          R = √ (2400² + 1600²)

          R = 2,994.4 km

for the angle of this displacement we use trigonometry

           tan θ = y / x

           θ = tan⁻¹ y / x

           θ = tan⁻¹ 1600 / (- 2400)

           θ = -33.7

3 0
3 years ago
Calculate the magnitude of the linear momentum for the following cases.
svet-max [94.6K]

Answer:

8.4335 x 10^-²¹, 1.78204 x 10²⁶

Explanation:

p = mv

p = (5.05 x 10⁶)(1.67 x 10^-²⁷)

p = 8.4335 x 10^-²¹

p = mv

p = (5.98 x 10²⁴)(2.98 x 10)

p = 1.78204 x 10²⁶

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lisov135 [29]
Answers B and D are true.
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What is the period of a spring that oscillates with a frequency of 2.09 Hz​
Sergio [31]

Frequency, υ = 2.09 Hz

We know that time period, T = 1/υ

∴ T = 1 ÷ 2.09

⇒ T = 0.4784 seconds

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Yes,and because not everyone can wink and often that someone can only wink with one eye only
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