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Sav [38]
3 years ago
15

Chemical A and Chemical B react in an exothermic reaction. What can be known about what will happen when Chemical A and Chemical

B are mixed together?
Please help. I'm confused.
Chemistry
1 answer:
Fynjy0 [20]3 years ago
8 0
In exothermic reactions, there is a release heat and the replacement of weak bonds with stronger ones.
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What form of energy is released into the atmosphere by the Earth’s surface?
MAVERICK [17]

Answer:

evaperation

Explanation:

remaining energy is transferred from the earth surface by evaporation

7 0
3 years ago
Read 2 more answers
Use significant digits to express the weight of a 150.0 lb person in kilograms ( 1 lb = 453.6 g)
slamgirl [31]

Answer:

150.0 = 68.038856

Explanation:

kilograms

4 0
2 years ago
How many grams of C6H6O3 will react with 97.0grams of O2?<br><br> C6H6O3+3O2 ===&gt; 6CO+3H2O
likoan [24]

Answer:

127.3 g

Explanation:

Data Given

mass of O₂= 97 g

mass of C₆H₆O₃ = ?

Reaction Given:

                C₆H₆O₃ + 3O₂ -------->  6CO + 3H₂O

Solution:

First find the mass of C₆H₆O₃ from the reaction that it combine with how many grams of oxygen (O₂).

Look at the balanced reaction

                  C₆H₆O₃  +   3O₂       -------->  6CO + 3H₂O

                    1 mol        3 mol

So 1 mole of C₆H₆O₃ combine with 3 moles of O₂  

Now

convert the moles into mass for which we have to know molar mass of C₆H₆O₃ and O₂

Molar mass of C₆H₆O₃

Molar mass of C₆H₆O₃ = 6(12) + 6(1) +3(16) = 72 + 6 + 48

Molar mass of C₆H₆O₃ = 126 g/mol

mass of C₆H₆O₃

                 mass in grams = no. of moles x molar mass

                 mass of C₆H₆O₃ = 1 mol x 126 g/mol

                 mass of C₆H₆O₃ = 126 g

Molar mass of O₂ = 2(16)

Molar mass of O₂= 32 g/mol

mass of O₂

                mass in grams = no. of moles x molar mass

                mass of O₂ = 3 mol x 32 g/mol

                 mass of O₂ = 96 g

So,

96 g of O₂ combine with 126 g of C₆H₆O₃ then how many grams of C₆H₆O₃ will combine with 97.0grams of O2

Apply unity Formula

                      96 g of O₂ ≅ 126 g of C₆H₆O₃

                      97 g of O₂ ≅  X g of C₆H₆O₃

By cross multiplication

                    X g of O₂ = 126 g x 97 g / 96 g

                   X g  of O₂ = 127.3 g

127.3 g of C₆H₆O₃ will combine with 97 g of O₂

So

mass of C₆H₆O =  127.3 g

7 0
3 years ago
Consider the above unbalanced equation. What volume of CO2 is produced at 270. mm Hg and 38.5°C when 0.820 g of C4H8 reacts with
irinina [24]

Answer:

The volume of CO2 is 4.20 L

Explanation:

Step 1: Data given

Pressure = 270 mm Hg =  260 /760 = 0.355263 atm

Temperature : 38.5 °C = 311.65 K

Mass of C4H8 = 0.820 grams

Step 2: The balanced equation

C4H8 + 6O2 → 4CO2 + 4H2O

Step 3: Calculate moles C4H8

Moles C4H8 = mass C4H8 / molar mass C4H8

Moles C4H8 = 0.820 grams / 56.11 g/mol

Moles C4H8 = 0.0146 moles

Step 4: Caalculate moles CO2

For 1 mol C4H8 we need 6 moles O2 to produce 4 moles CO2 and 4 moles H2O

For 0.0146 moles we'll have 4*0.0146 = 0.0584 moles CO2

Step 6: Calculate Volume CO2

p*V = n*R*T

V = (n*R*T) /p

⇒ with V = the volume of CO2 = TO BE DETERMINED

⇒ with n = the moles of CO2 = 0.0584 moles

⇒ with R = the gas constant = 0.08206 L*atm / mol*K

⇒ with T = The temperature = 311.65 K

⇒ with p = the pressure = 0.355263 atm

V = (0.0584 * 0.08206 * 311.65) / 0.355263

V = 4.20 L

The volume of CO2 is 4.20 L

8 0
3 years ago
Can somebody please help me with B and C if you can’t do them both just to be will give brain thanks
Vesnalui [34]

Answer:

Which class r u in hmm ? Tell me okay

8 0
3 years ago
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