Answer:
M of HI = 5.4 M.
Explanation:
- We have the rule: at neutralization, the no. of millimoles of acid is equal to the no. of millimoles of the base.
<em>(XMV) acid = (XMV) base.</em>
where, X is the no. of (H) or (OH) reproducible in acid or base, respectively.
M is the molarity of the acid or base.
V is the volume of the acid or base.
<em>(XMV) HI = (XMV) Ca(OH)₂.</em>
For HI; X = 1, M = ??? M, V = 25.0 mL.
For Ca(OH)₂, X = 2, M = 1.5 M, V = 45.0 mL.
<em>∴ M of HI = (XMV) Ca(OH)₂ / (XV) HI</em> = (2)(1.5 M)(45.0 mL) / (1)(25.0 mL) = <em>5.4 M.</em>
carbon, hydrogen, oxygen, and nitrogen are the most important elements!
Answer:
Therefore F ∠ 2.5N
Explanation:
Definition of Work:
It is the amount of energy transferred.
Mathematical expression:
W = F × d
By taking the friction into count it will define as:
Input work = work against friction × output work
No we will put the values:
25 J = w + 10 m
j = kg m²/s²
25 kg m²/s² = w + 10 m
when friction is exist then w > 0
25 kg m²/s² - 10 m > 0
15 N > 0
Therefore F ∠ 2.5N
