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Zarrin [17]
4 years ago
10

if 45.0 ml of 1.50 M Ca(OH)2 are needed to neutralize 25.0 ml of HI of unknown concentration, what is the molarity of the HI?

Chemistry
1 answer:
ipn [44]4 years ago
6 0

Answer:

M of HI = 5.4 M.

Explanation:

  • We have the rule: at neutralization, the no. of millimoles of acid is equal to the no. of millimoles of the base.

<em>(XMV) acid = (XMV) base.</em>

where, X is the no. of (H) or (OH) reproducible in acid or base, respectively.

M is the molarity of the acid or base.

V is the volume of the acid or base.

<em>(XMV) HI = (XMV) Ca(OH)₂.</em>

For HI; X = 1, M = ??? M, V = 25.0 mL.

For Ca(OH)₂, X = 2, M = 1.5 M, V = 45.0 mL.

<em>∴ M of HI = (XMV) Ca(OH)₂ / (XV) HI</em> = (2)(1.5 M)(45.0 mL) / (1)(25.0 mL) = <em>5.4 M.</em>

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Answer:

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Explanation:

Given data:

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Number of atoms = ?

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The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

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For example,

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8.28 mol×6.022 × 10²³  atoms / 1mol

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4 0
3 years ago
You are given a sample of an element with ONE valence electron.
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Answer:

the amount of valence electron, cna be found in the periodic table, which is called the atomic number which is top of the symbol

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5 0
3 years ago
A group of students working in a high school chemistry lab believe they have discovered a new element! How exciting? Upon furthe
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Answer:

Explanation:

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The atomic number would therefore be 74

For the mass number:

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From the peroidic table, tungsten(W) perfectly fits this description of the atom. It has an atomic number of 74 and a mass number of approximately 184. The element is not a new element.

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4 years ago
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