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Dennis_Churaev [7]
3 years ago
14

Physics // how i solve?

Physics
1 answer:
Alex3 years ago
7 0

V=IR

180mA=V/R

I=2V/3R

I=2/3 x 180 mA =120 mA

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A 0.09 g honeybee acquires a charge of +23 pc while flying. The earth's electric field near the surface is typically (100 N/C, d
hodyreva [135]

Answer:

2.6\times 10^{-5}

Explanation:

<u>Given:</u>

  • m = mass of the honeybee = 0.09 g = 9\times 10^{-5}\ kg
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<u>Assume:</u>

  • g = acceleration due to gravity = 9.8\ m/s^2
  • W = weight of the honeybee
  • F = electric force on the honeybee
  • R = ratio of the electric force and the weight of the honeybee

We know that

F = qE\,\,\, and\,\,\, W = mg\\\therefore R = \dfrac{F}{W}\\\Rightarrow R = \dfrac{qE}{mg}\\\Rightarrow R = \dfrac{2.3\times 10^{-11}\ C\times 100 N/C}{9\times 10^{-5}\ kg\times 9.8\ m/s^2}\\\Rightarrow R = 2.6\times 10^{-6}

So, the ration of the electric force on the bee to its weight is 2.6\times 10^{-6}.

On multiplying this ration by 10, the ratio becomes 2.6\times 10^{-5}.

8 0
4 years ago
Which of the following is not an equation of motion:- v=u+at; s=ut+at; v^2-u^2=2as; s=ut+1/2 at^2​
Sladkaya [172]

Answer:

s=ut+at

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8 0
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A coil with 25 turns of wire is moving in a uniform magnetic field of 1.5 T. The magnetic field is perpendicular to the plane of
leonid [27]

Given that,

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Lena [83]

Answer:

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8 0
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3 0
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