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musickatia [10]
3 years ago
15

"For punishment to work (i.e., to weaken the frequency of undesirable behaviors without creating a backlash), the punishment mus

t be strong enough to stop the undesired behavior and must be administered"
Physics
1 answer:
Flauer [41]3 years ago
3 0

Answer: Consistently,

Contingently and quickly

Explanation:

Consistently: it must follow a prescribed pattern and procedure putting the legal provisions in check.

Contingently: It must be administered in such a way that it is seen as dependent on the for a change character to occur. It should be administered putting into consideration of the undesirable character which are to be corrected.

Quickly: It must be administered on time,this is to ensure that the punishment gives immediate corrective action and prevent a reoccurrence of such undesirable character.

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Calcula el peso aparente de una bola de aluminio de 50 cm3, cuando se encuentra totalmente sumergida en alcohol. Datos: la densi
artcher [175]

Answer:

W_apparent = 93.1 kg

Explanation:

The apparent weight of a body is the weight due to the gravitational attraction minus the thrust due to the fluid where it will be found.

            W_apparent = W - B

The push is given by the expression of Archimeas

            B = ρ_fluide g V

            ρ_al = m / V

            m = ρ_al V

we substitute

            W_apparent = ρ_al V g - ρ_fluide g V

            W_apparent = g V (ρ_al - ρ_fluide)

       

we calculate

           W_apparent = 980 50 (2.7 - 0.8)

           W_apparent = 93100 g

            W_apparent = 93.1 kg

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2 years ago
A nation undergoing the transition from undeveloped to industrialized is commonly dependent on this to supply its energy needs.
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2 years ago
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Two equal positive charges are held in place at a fixed distance. If you put a third positive charge midway between these two ch
eimsori [14]

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Explanation:

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2 years ago
In what scientific study did scientists discover that when atoms split they _________.
Shtirlitz [24]

Answer:OOF

Explanation:

6 0
3 years ago
The force required to stretch a Hooke’s-law spring varies from 0 N to 63.5 N as we stretch the spring by moving one end 5.31 cm
Alika [10]

Answer:

Force constant will be 1195.85 N/m

Work done will be 1.6859 J

Explanation:

We have given the force,  F = 63.5 N

Spring is stretched by 5.31 cm

So x = 0.0531 m

Force is given , F = 63.5 N

We know that force is given by F=kx

So 63.5=k\times 0.0531

k = 1195.85 N/m

Now we have to find the work done

We know that work done is given by

W=\frac{1}{2}kx^2=\frac{1}{2}\times 1195.85\times 0.0531^2=1.6859J

8 0
3 years ago
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