Answer:
d' = 75.1 cm
Explanation:
It is given that,
The actual depth of a shallow pool is, d = 1 m
We need to find the apparent depth of the water in the pool. Let it is equal to d'.
We know that the refractive index is also defined as the ratio of real depth to the apparent depth. Let the refractive index of water is 1.33. So,
or
d' = 75.1 cm
So, the apparent depth is 75.1 cm.
The ball can't reach the speed of 20 m/s in two seconds, unless you THROW it down from the window with a little bit of initial speed. If you just drop it, then the highest speed it can have after two seconds is 19.6 m/s .
If an object starts from rest and its speed after 2 seconds is 20 m/s, then its acceleration is 20/2 = 10 m/s^2 .
(Gravity on Earth is only 9.8 m/s^2.)
Cool down the Slowest
B. Seawater, because it heats up slower and gives away heat slower than sand.
Read the question wrong the first time
The statement to every reacting there is, there is a opposite and same reacting.
hope it helps
Answer:
(a) T = 10 s
(b) f = 0.1 Hz
(c) λ = 32 m
(d) v = 3.2 m/s
(e) Insufficient data
Explanation:
(a)
Time period is defined as the time interval required for one wave to pass. Therefore, the time period can be given as:
T = Period = Time Taken/No. of Waves
T = 50 s/5
<u>T = 10 s</u>
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(b)
Frequency is the reciprocal of time period:
f = frequency = 1/T
f = 1/10 s
<u>f = 0.1 Hz</u>
<u></u>
(c)
Wavelength is the distance between two consecutive crests or troughs:
<u>λ = Wavelength = 32 m</u>
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(d)
Speed of wave is given by the following formula:
Speed = v = fλ
v = (0.1 Hz)(32 m)
v = 3.2 m/s
(e)
Amplitude cannot be found with given data.
