Answer:
(A) Q = 321.1C (B) I = 42.8A
Explanation:
(a)Given I = 55A−(0.65A/s2)t²
I = dQ/dt
dQ = I×dt
To get an expression for Q we integrate with respect to t.
So Q = ∫I×dt =∫[55−(0.65)t²]dt
Q = [55t – 0.65/3×t³]
Q between t=0 and t= 7.5s
Q = [55×(7.5 – 0) – 0.65/3(7.5³– 0³)]
Q = 321.1C
(b) For a constant current I in the same time interval
I = Q/t = 321.1/7.5 = 42.8A.
Answer:
The correct option is;
The atoms and molecules of the liquid water are moving, while the atoms and molecules of the glass are not moving
Explanation:
Matter that exist in the liquid or gaseous state consist of molecules that move freely about in the entire containing medium for gas, while the molecules move freely in the portion of the container occupied by the fluid in the case of liquid fluids
However, the molecules of a solid are fixed within the current shape of the solid and are only free to vibrate within a fixed location and the allow the passage of subatomic particles such as electrons
As such, the glass cup being a solid, consists of molecules fixed in space, while the liquid water consists of molecules which can translate within the portion of the volume of the glass filled with the water.
Answer:
I don't understand please interpret
Answer:
-100m/s not shure tho thx tho
Answer:
0.9432 m/s
Explanation:
We are given;
Mass of swimmer;m_s = 64.38 kg
Mass of log; m_l = 237 kg
Velocity of swimmer; v_s = 3.472 m/s
Now, if we consider the first log and the swimmer as our system, then the force between the swimmer and the log and the log and the swimmer are internal forces. Thus, there are no external forces and therefore momentum must be conserved.
So;
Initial momentum = final momentum
m_l × v_l = m_s × v_s
Where v_l is speed of the log relative to water
Making v_l the subject, we have;
v_l = (m_s × v_s)/m_l
Plugging in the relevant values, we have;
v_l = (64.38 × 3.472)/237
v_l = 0.9432 m/s
