1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Snezhnost [94]
3 years ago
9

GIVING BRAINLIEST PLEASE HELP ME!!!

Physics
2 answers:
Ne4ueva [31]3 years ago
6 0
1. b
2. c
3. A. Those are the answers
Butoxors [25]3 years ago
4 0

Answer:

Explanation:

1. Conduction

2. Convection

3. Radiation

You might be interested in
A 100 g aluminum calorimeter contains 250 g of water. The two substances are in thermal equilibrium at 10°C. Two metallic blocks
ipn [44]

Answer:

A. 1,950 J/kgºC

Explanation:

Assuming that all materials involved, finally arrive to a final state of thermal equilibrium, and neglecting any heat exchange through the walls of the calorimeter, the heat gained by the system "water+calorimeter" must be equal to the one lost by the copper and the unknown metal.

The equation that states how much heat is needed to change the temperature of a body in contact with another one, is as follows:

Q = c * m* Δt

where m is the mass of the body, Δt is the change in temperature due to the external heat, and c is a proportionality constant, different for each material, called specific heat.

In our case, we can write the following equality:

(cAl * mal * Δtal) + (cH₂₀*mw* Δtw) = (ccu*mcu*Δtcu) + (cₓ*mₓ*Δtₓ)

Replacing by the givens , and taking ccu = 0.385 J/gºC and cAl = 0.9 J/gºC, we have:

Qg= 0.9 J/gºC*100g*10ºC + 4.186 J/gºC*250g*10ºC  = 11,365 J(1)

Ql = 0.385 J/gºC*50g*55ºC + cₓ*66g*80ºC = 1,058.75 J + cx*66g*80ºC (2)

Based on all the previous assumptions, we have:

Qg = Ql

So, we can solve for cx, as follows:

cx = (11,365 J - 1,058.75 J) / 66g*80ºC = 1.95 J/gºC (3)

Expressing (3) in J/kgºC:

1.95 J/gºC * (1,000g/1 kg) = 1,950 J/kgºC

3 0
3 years ago
The speed of light in a vacuum is approximately 0.3 gm/s. What is the speed of light in meters per second?
klemol [59]

We have to convert Gm/s to m/s.

As  1 \ Gm/s = 10^9 \ m/s

Therefore the speed of light in vacuum,

c = 0.3 \ Gm/s = 0.3 \times 10^9 \ m/s \\\\ c= 3 \times 10^8 \ m/s

Thus, the speed of light in m/s is 3 \times 10^8 \ m/s

7 0
3 years ago
The low areas created as a sound wave propagates are called rarefactions
qwelly [4]

The answer is; pressure

The sound is a longitudinal wave meaning the particles vibrate parallel to the direction of the wave. Sound waves, therefore, produce compression (akin to the crest in a transverse wave) and rarefaction regions (akin to a trough in a transverse wave) as its energy is propagated in the medium.  


8 0
4 years ago
Read 2 more answers
Find the momentum (in kg.m/s) of a helium nucleus having a mass of 6.68 x 10^-27 kg that is moving at 0.386c.
igomit [66]

Answer:

7.73544\times 10^{-21}kgm/sec

Explanation:

We have given mass of helium nucleus m=6.68\times 10^{-27}kg

Velocity of helium nucleus v=0.386c=0.386\times 3\times 10^{8}m/sec=1.158\times 10^{8}m/sec

Momentum of the helium nucleus is given by P=mv where m is mass and v is velocity

So P=mv=6.68\times 10^{-27}\times 1.158\times 10^{8}=7.73544\times 10^{-21}kgm/sec

6 0
3 years ago
A policeman, parked at arn intersection, is passed by a speeder traveling at 120 km/hr. Two seconds later, the policeman starts
pashok25 [27]

Answer:

682.32 m

Explanation:

Speed of the passing speeder = 120 km/hr = 120 × 0.2777 = 33.33 m/s

time after which police man starts = 2 seconds

Acceleration of the policeman = 4.0 m/s²

let the time taken to catch be 't' seconds

Now,

The total distance to be covered by the policeman

= Distance covered by the speeder in the 2 seconds + Distance further traveled by the speeder in time t

thus,

From Newton's equation of motion

s=ut+\frac{1}{2}at^2

where,  

s is the total distance traveled by the police man

u is the initial speed  = 0

a is the acceleration

t is the time

thus,

0\times t+\frac{1}{2}\times4t^2= 33.33 × 2 + 33.33 × t

or

2t² = 66.66 + 33.33t

or

2t² - 33.33t - 66.66 = 0

on solving the above equation, we get

t = 18.47 seconds (negative value is ignored as time cannot be negative)

therefore,

the total distance covered = 33.33 × 2 + 33.33 × 18.47 = 682.32 m

7 0
3 years ago
Other questions:
  • The greater the speed of speed gas particles in containers, the
    13·1 answer
  • What is the question
    6·1 answer
  • a car company claims that its car can accelerate from rest to a speed of 28.0 m/s in 20.0 s. find the average acceleration of th
    14·1 answer
  • The force of friction on a sliding object is 10 N. The applied force needed to maintain a constant velocity is
    10·1 answer
  • Anyone please??? will rate brainless and would help a lot please
    10·1 answer
  • A runner accelerates to 4.2 m/s2 for 10 seconds before winning the race. How far did he/she run?
    10·2 answers
  • What is the charge of a Sulfur atom if it has 17 electrons?
    12·1 answer
  • Parking orbit is defined accurately by (a) 1" Kepler's law (b) 2 Kepler's law (c) 2 and 3 Kepler's law (d) 3" Kepler's law​
    6·1 answer
  • When will the human brain be fully developed?
    12·2 answers
  • niobium metal becomes a superconductor when cooled below 9 k. its superconductivity is destroyed when the surface magnetic field
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!