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3 years ago

For these last four question list the net force and direction.

Physics

1 answer:

alex41 [277]3 years ago

3 0

1. 20 N right

2. 4N Up

3. 4N up

4. 2N

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we measure a voltage difference of 5.0 V between two points on the conducting paper between two parallel conducting electrodes.

Alex17521 [72]

Answer:

E=1824.81 V/m

Explanation:

Given that

Voltage difference = 5 V

Distance ,D= 3 mm

θ = 24°

As we know that electric filed given as

$E=\dfrac{V}{d}$

Given that D is 24° with respect to the perpendicular to the electrodes.So we have to take cos component of D.

d= D cosθ

d= 3 cos24°

d = 2.74 mm

$E=\dfrac{V}{d}$

$E=\dfrac{5}{2.74\times 10^{-3}}$

E=1824.81 V/m

8 0

3 years ago

An ant walks 2\,\text m2m2, start text, m, end text to the right and then climbs 1 \,\text m1m1, start text, m, end text up a wa

NNADVOKAT [17]

Answer:

26.56°

Explanation:

given,

horizontal distance travel by the ant = 2 m

vertical distance travel by the ant = 1 m

angle of the ant above the initial point = ?

using trigonometric function

$tan \theta = \dfrac{h}{x}$

θ is the angle of the ant form initial position

h is the height on the wall

x is the horizontal distance covered by the ant

$tan \theta = \dfrac{1}{2}$

$\theta =tan^{-1}(0.5)$

$\theta =26.56^0$

hence, the angle made by the ant from the initial position is equal to 26.56°

3 0

3 years ago

Two identical automobiles are

Phantasy [73]

Answer:

i think that it is b but I could be wrong

3 0

3 years ago

Why is the absolute magnitude of some stars greater than their apparent magnitude

SSSSS [86.1K]

<span>answer under the link: http: //briskrange.com/7gAl</span>

6 0

4 years ago

A passenger on an interplanetary express bus traveling at = 0.95 takes a 9.0-minute catnap, according to her watch.How long does

Nimfa-mama [501]

Answer:

28.82 minutes

Explanation:

This problem is an example of time dilatation by acceleration. The formula is:

$\Delta t=\gamma \Delta t_0=\frac{\Delta t_0}{\sqrt{1-\frac{v^2}{c^2} }}$

$\Delta t$ is the time measured by the observer on a fixed position (in this case in the fixed planet), $\Delta t_0$ is the time measured by the person moving away from the fixed observer (the one on an interplanetary express bus), $c$ is the speed of light and $v$ the velocity of the observer that is moving away (the velocity of the ship).

$\Delta t_0=9 min=540s\\\Delta t=\frac{540}{\sqrt{1-\frac{(0.95c)^2}{c^2}}}=\frac{540}{\sqrt{1-\frac{0.95^2c^2}{c^2}}}=\frac{540}{\sqrt{1-0.95^2}}\\\Delta t=\frac{540}{\sqrt{1-0.9025}}=\frac{540}{\sqrt{0.0975}}=\frac{540}{0.3122}=1729.38s\\\Delta t=28.82minutes$

6 0

4 years ago