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polet [3.4K]
3 years ago
6

Hbr(aq)+h2o(l)→h3o+(aq)+br−(aq) express your answers as a chemical expressions. enter your answers in order given in the questio

n separated by commas.
Chemistry
1 answer:
tamaranim1 [39]3 years ago
8 0

This is an incomplete question, here is a complete question.

For each reaction, identify the Bronsted-Lowry acid, the Bronsted-Lowry base, the conjugate acid, and the conjugate base.

HBr(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+Br^-(aq)

Express your answers as a chemical expressions. Enter your answers in order given in the question separated by commas.

Answer : The given equilibrium reaction will be,

HBr(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+Br^-(aq)

Acid            Base      Conjugate    Conjugate

                                       acid             base

Explanation :

According to the Bronsted Lowry concept, Bronsted Lowry-acid is a substance that donates one or more hydrogen ion in a reaction and Bronsted Lowry-base is a substance that accepts one or more hydrogen ion in a reaction.

Or we can say that, conjugate acid is proton donor and conjugate base is proton acceptor.

The given equilibrium reaction will be,

HBr(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+Br^-(aq)

Acid            Base      Conjugate    Conjugate

                                       acid             base

In this reaction, HBr is an acid that donate a proton or hydrogen to H_2O base and it forms Br^- and H_3O^+ are conjugate base and acid respectively.

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H₂O₄

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If liquid water is exposed to normal atmospheric pressure, what needs to change in order to change its state of matter?
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Mass of water because then it will change his States of matter
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The combustion of 1.5011.501 g of fructose, C6H12O6(s)C6H12O6(s) , in a bomb calorimeter with a heat capacity of 5.205.20 kJ/°C
avanturin [10]

Answer : The internal energy change is -2805.8 kJ/mol

Explanation :

First we have to calculate the heat gained by the calorimeter.

q=c\times (T_{final}-T_{initial})

where,

q = heat gained = ?

c = specific heat = 5.20kJ/^oC

T_{final} = final temperature = 27.43^oC

T_{initial} = initial temperature = 22.93^oC

Now put all the given values in the above formula, we get:

q=5.20kJ/^oC\times (27.43-22.93)^oC

q=23.4kJ

Now we have to calculate the enthalpy change during the reaction.

\Delta H=-\frac{q}{n}

where,

\Delta H = enthalpy change = ?

q = heat gained = 23.4 kJ

n = number of moles fructose = \frac{\text{Mass of fructose}}{\text{Molar mass of fructose}}=\frac{1.501g}{180g/mol}=0.00834mole

\Delta H=-\frac{23.4kJ}{0.00834mole}=-2805.8kJ/mole

Therefore, the enthalpy change during the reaction is -2805.8 kJ/mole

Now we have to calculate the internal energy change for the combustion of 1.501 g of fructose.

Formula used :

\Delta H=\Delta U+\Delta n_gRT

or,

\Delta U=\Delta H-\Delta n_gRT

where,

\Delta H = change in enthalpy = -2805.8kJ/mol

\Delta U = change in internal energy = ?

\Delta n_g = change in moles = 0   (from the reaction)

R = gas constant = 8.314 J/mol.K

T = temperature = 27.43^oC=273+27.43=300.43K

Now put all the given values in the above formula, we get:

\Delta U=\Delta H-\Delta n_gRT

\Delta U=(-2805.8kJ/mol)-[0mol\times 8.314J/mol.K\times 300.43K

\Delta U=-2805.8kJ/mol-0

\Delta U=-2805.8kJ/mol

Therefore, the internal energy change is -2805.8 kJ/mol

5 0
3 years ago
Select the correct answer. What is heat of vaporization? A. It is the heat required to change a substance’s temperature by 1°C.
Luba_88 [7]

D. It is the heat required to change a gram of substance from a liquid to a gas.

Explanation:

The heat of vaporization is the heat required to change a gram of substance from a liquid to a gas.

  • It is also known as the enthalpy of vaporization.
  • The heat of vaporization is the quantity of heat needed to change one gram of a substance from liquid to gas.
  • This heat of vaporization is dependent on the pressure conditions the process is taking place.
  • Different liquids have their heat of vaporization.

learn more:

Heat of vaporization brainly.com/question/9529654

#learnwithBrainly

7 0
3 years ago
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