Heating a carboxylic acid with a primary amine forms water along with what organic product? OA) A secondary amide OB) A primary
1 answer:
Answer:
A) secondary amide
Explanation:
When carboxylic acid reacts with a primary amine, a condensation reaction takes place with the elimination of a water molecule .
For example, ethanol reacts with methylamine which is a primary amine gives N-Methylacetamide and a water molecule as:
The bond formed which is
O
||
-- C ---NH ---
is known as secondary amide group as only one hydrogen is attached to nitrogen atom in the amide bond.
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Barium : 
with +2 being the charge
Oxygen :
with -2 being the charge
The given equation can be written as:
Ba + O = BaO
Since the sum charges of Barium and Oxygen equals 0, there is no need to add subscripts.
Both Ba and O appear on the left and right side of the equation once, so there is no need to add a coefficient.
Ba + O = BaO is balanced
Oxygen :
The given equation can be written as:
Ba + O = BaO
Since the sum charges of Barium and Oxygen equals 0, there is no need to add subscripts.
Both Ba and O appear on the left and right side of the equation once, so there is no need to add a coefficient.
Ba + O = BaO is balanced
Answer:
P₂ = 1.12 atm
Explanation:
To find the new pressure, you need to use the Combined Gas Law:
In this equation, "P₁", "V₁", and "T₁" represent the initial pressure, volume, and temperature. "P₂", "V₂", and "T₂" represent the new pressure, volume, and temperature. Before plugging the values into the equation, you need to
(1) convert the pressure from mmHg to atm (760 mmHg = 1 atm)
(2) convert the temperatures from Celsius to Kelvin (°C + 273)
The final answer should have 3 sig figs like the given values.
P₁ = 365 mmHg / 760 = 0.480 atm P₂ = ? atm
V₁ = 5.00 L V₂ = 2.30 L
T₁ = 20°C + 273 = 293 K T₂ = 40°C + 273 = 313 K
<----- Combined Gas Law
<----- Insert values
<----- Simplify left side
<----- Multiply both sides by 313
<----- Divide both sides by 2.30