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jenyasd209 [6]
4 years ago
9

Write code to compare two numbers. The code should check whether the first number is less than or equal to the second and then d

isplay the result on the serial monitor.
Physics
1 answer:
belka [17]4 years ago
7 0

Answer:

Explanation:

I will be using Python 3 syntax in writing the code.

- First we need to define a Function 'compare_number' that parse in 2 variables x and y to be compared.

- Then we use the conditional statement if/else to check for the conditions.

- Finally, we will return a Boolean operator True/False or rather print out the statement result to the console. The code is as shown below.

def compare_numbers (x, y):

if x <= y:

return True

else:

return False

compare_number (2,3)

Since 2 is less than 3, the result that will be displayed on the console will be True.

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A rod of length L is hinged at one end. The moment of inertia as the rod rotates around that hinge is ML2 /3. Suppose a 2.00-m r
Stels [109]

To solve this problem we will apply the concepts related to the moment of inertia and Torque, the latter both its translational and rotational expression.

According to the information given the moment of inertia of the body would be

I = \frac{1}{3} mL^2

Replacing we have

I = \frac{1}{3} (3kg)(2m)^2

I = 4 kg * m^2

Now the translational torque would be the product between the force applied (Its own Weight) and the distance (Its center of mass at the middle)

\tau = F*r

\tau = mg (\frac{L}{2})

\tau = (3)(9.8)(\frac{2}{2})

\tau = 29.4N\cdot m

Now the rotational torque is defined as the product between the moment of inertia and the angular acceleration, then,

\tau = I\alpha \rightarrow \alpha = \frac{\tau}{I}

Replacing,

\alpha = \frac{29.4}{4}

\alpha =7.35 rad / s^2

Therefore the angular acceleration is 7.35rad/s^2

4 0
3 years ago
A mass of 5 kg is moving at 5 m/s when it collides with another mass of 2 kg moving in the same direction at 2 m/s. After the co
Burka [1]

Answer:

4.14 m/s

Explanation:

m¹u¹+m²u²=(m¹+m²)v

5(5)+2(2)=(5+2)v

25+4=7v

29=7v

29/7=v

v=4.14 m/s

3 0
4 years ago
Find velocity gradient
Artist 52 [7]

Explanation:

velocity gradient= velocity/distance

6 0
3 years ago
Which statement best compares potential and kinetic energy?
Eddi Din [679]

Answer:

I think option 1st is correct

lf it is wrong I apologise

HAVE A NICE DAY

8 0
3 years ago
Read 2 more answers
A proton is released from rest at the positive plate of a parallelplatecapacitor. It crosses the capacitor and reaches the negat
Triss [41]

Answer:

2.1406 ×10^6 m/sec

Explanation:

we know that energy is always conserved

so from the law of energy conservation

qV=\frac{1}{2}mv^2

here V is the potential difference  

we know that mass of proton = 1.67×10^{-27} kg

we have given speed =50000m/sec

so potential difference V=\frac{\frac{1}{2}\times 1.67\times 10^{-27}50000^2}{1.6\times 10^{-19}}=13.045

now mass of electron =9.11×10^{-31}

so for electron

\frac{1}{2}\times 9.11\times 10^{-31}v^2=1.6\times 10^{-19}\times 13.045=2.1406\times 10^6 m/sec

so the velocity of electron will be 2.1406×10^6 m/sec

4 0
3 years ago
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