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emmainna [20.7K]
3 years ago
9

Calculate the charge that flows through the cell in 1 minute. Each filament lamp has a power of 3 W and a resistance of 12 Ω

Physics
1 answer:
lapo4ka [179]3 years ago
5 0

Answer:

24 Coulumbs

Explanation:

Given data

time= 1 minute= 6 seconds

P=2 W

R= 12 ohm

We know that

P= I^2R

P/R= I^2

2/12= I^2

I^2= 0.166

I= √0.166

I= 0.4 amps

We know also that

Q= It

substitute

Q= 0.4*60

Q= 24 Columbs

Hence the charge is 24 Coulumbs

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Answer:

2.22m/s

Explanation:

Given parameters:

M1  = 60kg

M2  = 75kg

V1  = 0m/s

V2  = 4m/s

Unknown;

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Solution:

To solve this problem, we must understand that the momentum before and after collision of the bodies must be the same;

     M1 V1  + M2 V2  = v(M1 + M2)

So;

       60 x 0  +  75 x 4  = v (60 +75)

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3 years ago
What type of stretch is responsible for squeezing rock?
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<span>Compressional stress</span>
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When object 1 came into contact with object 2, object 2 got warmer. what can be concluded about the objects before they came int
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The statement that is true regarding the objects is that object 1 had faster-moving particles, which is option 2. Details about matter can be found below.

<h3>What is matter?</h3>

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7 0
2 years ago
A 51 kg woman skis down a hill and her kinetic energy is 9.96e4 j. What is her speed?
arlik [135]

Kinetic energy of woman is given as

KE = 9.96 \times 10^4 J

mass of woman is given as

m = 51 kg

now we will have

KE = \frac{1}{2}mv^2

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8 0
4 years ago
What is strength of the electric field between two parallel conducting plates separated by 1.00 cm and having an electric potent
Alex17521 [72]

Answer:

Electric field will be 1.5\times 10^{6}V/m

Explanation:

We have given potential difference between the two plates = 15000 volt

Distance between the plates = d=1cm=10^{-2}m

We have to find the electric field strength between the plates

Potential difference between the plates is equal to V=Ed

So electric field strength will be E=\frac{V}{d}=\frac{15000}{10^{-2}}=1.5\times 10^{6}V/m

So electric field will be 1.5\times 10^{6}V/m

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