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Rashid [163]
4 years ago
6

A high molecular weight hydrocarbon gas A is fed continuously into a heated mixed flow reactor (0.1liter) where it is thermally

cracked into lower molecular weight materials collectively called R as the reaction stoichiometry A 5R. Find the space velocity if molar feed rate was 300millimol/ hr and the feed concentration was 100millimol / lit.
Engineering
1 answer:
dimulka [17.4K]4 years ago
5 0

Answer:

Space velocity = 30 hr⁻¹

Explanation:

Space velocity for reactors express how much reactor volume of feed or reactants can be treated per unit time. For example, a space velocity of 3 hr⁻¹ means the reactor can process 3 times its volume per hour.

It is given mathematically as

Space velocity = (volumetric flow rate of the reactants)/(the reactor volume)

Volumetric flowrate of the reeactants

= (molar flow rate)/(concentration)

Molar flowrate of the reactants = 300 millimol/hr

Concentration of the reactants = 100 millimol/liter

Volumetric flowrate of the reactants = (300/100) = 3 liters/hr

Reactor volume = 0.1 liter

Space velocity = (3/0.1) = 30 /hr = 30 hr⁻¹

Hope this Helps!!!

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Answer:

a)

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b)

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c)

α in eutectic mixture = 0.062

Explanation:

Assumptions:

(i) the  system is in thermal equilibrium with its surroundings

(ii) There are no impurities or other alloying elements present

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(b) Determine the mass fractions of primary α and eutectic microconstituents

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mass fraction of primary α (Wα) = (Ceutetic - C0) / (Ceutetic - Cα) = (71.9 - 25) / (71.9 - 8) = 0.734

mass fraction of  eutectic micro-constituents (We) = (C0 - Cα) / (Ceutetic - Cα) = (25 - 8) / (71.9 - 8) = 0.266

(c) Determine the mass fraction of eutectic α.

From the eutetic reaction, L  ↔    α + β

Total α = Primary α + α in eutectic mixture

Therefore: α in eutectic mixture = Total α - Primary α = 0.796 - 0.734 = 0.062

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Answer:

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