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kupik [55]
2 years ago
7

Which of the following identifies the limitations of green engineering?

Engineering
1 answer:
olga_2 [115]2 years ago
4 0

Answer:

Resources and Cost

Explanation:

  • Cost: Sustainable choices can value a lot of as a result of they price makers more to provide. Thus, there'll always be an oversized initial investment once selecting a green element for your home.
  • Resources: Sustainable materials don't seem to be always as without delay available as their less eco-friendly alternatives.

Hope it helps!<3

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An engineer is designing a total hip implant. She intends to make the femoral stem out of titanium because it forms a good inter
makvit [3.9K]

Answer:

1. Yes.

2. Localized corrosion

Explanation:

Should she be worried about corrosion?

Yes, the engineer needs to be worried about corrosion as stainless steel has a lower resistance to corrosion, in other words, stainless steel corrodes faster than Titanium.

If so, what types of corrosion could take place?

The type of corrosion that takes place is called Localized corrosion. Localized corrosion occurs when a small part of a component experiences corrosion. In this case, the ball component of the femoral stem is made of stainless steel which will corrode faster than the other parts of the femoral stem which is made of Titanium.

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3 years ago
Worth 20 points! Please help ASAP!
gulaghasi [49]

Answer:

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Explanation:

8 0
3 years ago
A very large plate is placed equidistant between two vertical walls. The 10-mm spacing between the plate and each wall is filled
Vikentia [17]

Answer:

Force per unit plate area is 0.1344 N/m^{2}

Solution:

As per the question:

The spacing between each wall and the plate, d = 10 mm = 0.01 m

Absolute viscosity of the liquid, \mu =1.92\times 10^{- 3} Pa-s

Speed, v = 35 mm/s = 0.035 m/s

Now,

Suppose the drag force that exist between each wall and plate is F and F' respectively:

Net Drag Force = F' + F''

F = \tau A

where

\tau = shear stress

A = Cross - sectional Area

Therefore,

Net Drag Force, F = (\tau ' +\tau '')A

\frac{F}{A} = \tau ' +\tau ''

Also

F = \frac{\mu v}{d}

where

\mu = dynamic coefficient of viscosity

Pressure, P = \frac{F}{A}

Therefore,

\frac{F}{A} = \frac{\mu v}{d} + \frac{\mu v}{d} = 2\frac{\mu v}{d}

\frac{F}{A} = 2\frac{1.92\times 10^{- 3}\times 0.035}{0.010} = 0.01344 N/m^{2}

8 0
3 years ago
A geothermal heat pump absorbs 15 KJ/s of heat from the Earth 15 m below a house. This heat pump uses a 7.45 kJ/s compressor.
Oxana [17]

Answer:

COP of heat pump=3.013

COP of cycle=1.124

Explanation

W = Q2 - Q1 ----- equation 1

W = work done

Q2 = final energy

Q1 = initial energy

A) calculate the COP of the heat pump

COP =Q2/W

from equation 1

Q2 = Q1 + W = 15 + 7.45 = 22.45 KW

therefore COP =22.45/7.45  = 3.013

B) COP when cycle is reversed

COP = Q1/W

from equation 1

Q1 + W = Q2 ------ equation 2

Q2 = 15 Btu/s = 15 * 1.055 = 15.825 KW therefore from equation 2

Q1 = 8.375 KW

COP =8.375/7.45   = 1.124

6 0
3 years ago
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Please solve part two
Burka [1]

Answer:

Wat part 2

Explanation:

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