Key term of Bimetal strip

Write a program that prompts for a line of text and then transforms the text based on chosen actions. Actions include reversing

nlexa [21]

Answer:

public class TextConverterDemo

{

//Method definition of action1337

public static String action1337(String current)

{

//Replace each L or l with a 1 (numeral one)

current = current.replace('L', '1');

current = current.replace('l', '1');

//Replace each E or e with a 3 (numeral three)

current = current.replace('E', '3');

current = current.replace('e', '3');

//Replace each T or t with a 7 (numeral seven)

current = current.replace('T', '7');

current = current.replace('t', '7');

//Replace each O or o with a 0 (numeral zero)

current = current.replace('O', '0');

current = current.replace('o', '0');

//Replace each S or s with a $ (dollar sign)

current = current.replace('S', '$');

current = current.replace('s', '$');

return current;

}

//Method definition of actionReverse

//This method is used to reverses the order of

//characters in the current string

public static String actionReverse(String current)

{

//Create a StringBuilder's object

StringBuilder originalStr = new StringBuilder();

//Append the original string to the StribgBuilder's object

originalStr.append(current);

//Use reverse method to reverse the original string

originalStr = originalStr.reverse();

//return the string in reversed order

return originalStr.toString();

}

//Method definition of main

public static void main(String[] args)

{

//Declare variables

String input, action;

//Prompt the input message

System.out.println("Welcome to the Text Converter.");

System.out.println("Available Actions:");

System.out.println("\t1337) convert to 1337-speak");

System.out.println("\trev) reverse the string");

System.out.print("Please enter a string: ");

//Create a Scanner class's object

Scanner scn = new Scanner(System.in);

//Read input from the user

input = scn.nextLine();

do

{

/*Based on the action the user chooses, call the appropriate

* action method. If an unrecognized action is entered then

* the message "Unrecognized action." should be shown on a

* line by itself and then the user is prompted again just

* as they were when an action was performed.

* */

System.out.print("Action (1337, rev, quit): ");

action = scn.nextLine();

if (action.equals("1337"))

{

input = action1337(input);

System.out.println(input);

} else if (action.equals("rev"))

{

input = actionReverse(input);

System.out.println(input);

} else if (!action.equals("quit"))

{

System.out.println("Unrecognized action.");

}

} while (!action.equals("quit"));

System.out.println("See you next time!");

scn.close();

}

7 0

2 years ago

A company purchases a certain kind of electronic device from a manufacturer. The manufacturer indicates that the defective rate

olga2289 [7]

Answer:

1) The probability of at least 1 defective is approximately 45.621%

2) The probability that there will be exactly 3 shipments each containing at least 1 defective device among the 20 devices that are tested from the shipment is approximately 16.0212%

Explanation:

The given parameters are;

The defective rate of the device = 3%

Therefore, the probability that a selected device will be defective, p = 3/100

The probability of at least one defective item in 20 items inspected is given by binomial theorem as follows;

The probability that a device is mot defective, q = 1 - p = 1 - 3/100 = 97/100 = 0.97

The probability of 0 defective in 20 = ₂₀C₀(0.03)⁰·(0.97)²⁰ ≈ 0.543794342927

The probability of at least 1 = 1 - The probability of 0 defective in 20

∴ The probability of at least 1 = 1 - 0.543794342927 = 0.45621

The probability of at least 1 defective ≈ 0.45621 = 45.621%

2) The probability of at least 1 defective in a shipment, p ≈ 0.45621

Therefore, the probability of not exactly 1 defective = q = 1 - p

∴ q ≈ 1 - 0.45621 = 0.54379

The probability of exactly 3 shipment with at least 1 defective, P(Exactly 3 with at least 1) is given as follows;

P(Exactly 3 with at least 1) = ₁₀C₃(0.45621)³(0.54379)⁷ ≈ 0.160212

Therefore, the probability that there will be exactly 3 shipments each containing at least 1 defective device among the 20 devices that are tested from the shipment is 16.0212%

4 0

2 years ago

One good way to improve your gas Milage is to ___.

VashaNatasha [74]

Answer: B

Explanation:

One good way to improve your gas mileage is to accelerate smoothly and directly to a safe speed.

Hope this helps!

5 0

2 years ago

Read 2 more answers

How do you keep the weight evenly distributed on a trailered boat?

Neporo4naja [7]

C because i know what i’m taking about

7 0

3 years ago

P10.12. A certain amplifier has an open-circuit voltage gain of unity, an input resistance of and an output resistance of The si

klio [65]

complete question

A certain amplifier has an open-circuit voltage gain of unity, an input resistance of 1 \mathrm{M} \Omega1MΩ and an output resistance of 100 \Omega100Ω The signal source has an internal voltage of 5 V rms and an internal resistance of 100 \mathrm{k} \Omega.100kΩ. The load resistance is 50 \Omega.50Ω. If the signal source is connected to the amplifier input terminals and the load is connected to the output terminals, find the voltage across the load and the power delivered to the load. Next, consider connecting the load directly across the signal source without the amplifier, and again find the load voltage and power. Compare the results. What do you conclude about the usefulness of a unity-gain amplifier in delivering signal power to a load?

Answer:

3.03 V 0.184 W

2.499 mV 125*10^-9 W

Explanation:

First, apply voltage-divider principle to the input circuit: 1

$V_{i}= (R_i/R_i+R_s) *V_s = 10^6/10^6+(0.1*10^6)\\$ *5

= 4.545 V

The voltage produced by the voltage-controlled source is:

A_voc*V_i = 4.545 V

We can find voltage across the load, again by using voltage-divider principle:

V_o = A_voc*V_i*(R_o/R_l+R_o)

= 4.545*(100/100+50)

= 3.03 V

Now we can determine delivered power:

P_L = V_o^2/R_L

= 0.184 W

Apply voltage-divider principle to the circuit:

V_o = (R_o/R_o+R_s)*V_s

= 50/50+100*10^3*5

= 2.499 mV

Now we can determine delivered power:

P_l = V_o^2/R_l

= 125*10^-9 W

Delivered power to the load is significantly higher in case when we used amplifier, so a unity gain amplifier can be useful in situation when we want to deliver more power to the load. It is the same case with the voltage, no matter that we used amplifier with voltage open-circuit gain of unity.

4 0

2 years ago