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kobusy [5.1K]
3 years ago
9

A Michelson interferometer operating at a 500 nm wavelength has a 3.73-cm-long glass cell in one arm. To begin, the air is pumpe

d out of the cell and mirror M2 is adjusted to produce a bright spot at the center of the interference pattern. Then, a valve is opened and air is slowly admitted into the cell. The index of refraction of air at 1.00 atm pressure is 1.00028.
How many bright-dark-bright fringe shifts are observed as the cell fills with air?
Engineering
1 answer:
LekaFEV [45]3 years ago
6 0

Answer:

The number of bright-dark fringe is 42

Solution:

As per the question:

Wavelength of light, \lambda = 500\ nm = 500\times 10^{- 9}\ m

Length of the glass cell, x = 3.73 cm = 0.0373 m

Refractive index, \mu = 1.00028

Now,

To calculate the bright-dark fringe shifts, we use the formula given below:

d_{m} = \frac{2x}{\lambda }\times (\mu - 1)

Now, substituting the appropriate values in the above formula:

d_{m} = \frac{2\times 0.0373}{500\times 10^{- 9}}\times (1.00028 - 1)

d_{m} = 41.77 ≈ 42

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please find attached.

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