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kobusy [5.1K]
3 years ago
9

A Michelson interferometer operating at a 500 nm wavelength has a 3.73-cm-long glass cell in one arm. To begin, the air is pumpe

d out of the cell and mirror M2 is adjusted to produce a bright spot at the center of the interference pattern. Then, a valve is opened and air is slowly admitted into the cell. The index of refraction of air at 1.00 atm pressure is 1.00028.
How many bright-dark-bright fringe shifts are observed as the cell fills with air?
Engineering
1 answer:
LekaFEV [45]3 years ago
6 0

Answer:

The number of bright-dark fringe is 42

Solution:

As per the question:

Wavelength of light, \lambda = 500\ nm = 500\times 10^{- 9}\ m

Length of the glass cell, x = 3.73 cm = 0.0373 m

Refractive index, \mu = 1.00028

Now,

To calculate the bright-dark fringe shifts, we use the formula given below:

d_{m} = \frac{2x}{\lambda }\times (\mu - 1)

Now, substituting the appropriate values in the above formula:

d_{m} = \frac{2\times 0.0373}{500\times 10^{- 9}}\times (1.00028 - 1)

d_{m} = 41.77 ≈ 42

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GenaCL600 [577]

Answer:

62.14\ \text{miles}

6213727.37\ \text{miles}

Explanation:

The distance of the chain would be the product of the dislocation density and the volume of the metal.

Dislocation density = 10^5\ \text{mm}^{-2}

Volume of the metal = 1000\ \text{mm}^3

10^5\times 1000=10^8\ \text{mm}\\ =10^5\ \text{m}

1\ \text{mile}=1609.34\ \text{m}

\dfrac{10^5}{1609.34}=62.14\ \text{miles}

The chain would extend 62.14\ \text{miles}

Dislocation density = 10^{10}\ \text{mm}^{-2}

Volume of the metal = 1000\ \text{mm}^3

10^{10}\times 1000=10^{13}\ \text{mm}\\ =10^{10}\ \text{m}

\dfrac{10^{10}}{1609.34}=6213727.37\ \text{miles}

The chain would extend 6213727.37\ \text{miles}

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2 years ago
Tanya Pierce, President and owner of Florida Now Real Estate is seeking your assistance in designing a database for her business
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Answer:

the answer is attributes for each entity

5 0
3 years ago
The angle of twist can be computed using the material’s shear modulus if and only if: (a)- The shear stress is still in the elas
ollegr [7]

Answer:

The angle of twist can be computed using the material’s shear modulus if and only if the shear stress is still in the elastic region

Explanation:

The shear modulus (G) is the ratio of shear stress to shear strain. Like the modulus of elasticity, the shear modulus is governed by Hooke’s Law: the relationship between shear stress and shear strain is proportional up to the proportional limit of the material. The angle of twist can be computed using the material’s shear modulus if and only if the shear stress is still in the elastic region.

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3 years ago
When an object is moving, we use the following coefficient for friction calculations a)-μk b)-μs c)-γk d)- γs
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Answer:\mu_{k}

Explanation:

We use kinetic friction when a body is moving i.e. \mu_{k} for calculations.

Static friction is used when a body is in rest while kinetic friction is used when a body is moving and its value is quite low as compared to static friction .

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3 years ago
The domain of discourse is the members of a chess club. The predicate B(x, y) means that person x has beaten person y at some po
satela [25.4K]

Answer:A. No one has ever beat Nancy.

Explanation:

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The dormain of discourse is also known simply as universe, can also be said to be a set of entities o

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THE LOGICAL UNDERSTANDING OF THE THE QUESTION IS THAT NO ONE HAS EVER BEAT NANCY.

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