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schepotkina [342]
3 years ago
5

What is the explicit formula for -5, 10, -20, 40,...

Mathematics
1 answer:
algol [13]3 years ago
3 0
You multiply by -2 every time.

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A jar contains 100 tickets for a drawing. Among those tickets are 7 winning tickets. What are the odds in favor of winning?
noname [10]

Answer:

i say 7/100

Step-by-step explanation:

if the 100 tickets is your total then its your denominator

the 7 is represents the tickets what are winners

3 0
3 years ago
The weight of and object on the moon, m, is about 1/6 of the object's weight on earth, e. Which equation represent the approxima
denis23 [38]
M (m) is (=) 1/6 of (1/6 times) earth weight (e)
m=1/6 times e
m=e/6

B is the answer
8 0
3 years ago
Answer this ??
nevsk [136]
There would be 31 animals.
6 0
4 years ago
A 30-60-90 triangle with a hypotenuse of 6 . Find the length of all other sides
andrew-mc [135]
1.  Find the "opposite side," if the angle is 60 degrees and the hyp is 6:
     
                            opp        opp      sqrt(3)
      sin 60 deg = ------- = -------- = ----------
                            hyp          6             2

      Cross-multiplying, 2(opp) = 6sqrt(3), so that opp = 3 sqrt(3) (answer)

2.  Use the Pyth. Thm. to find the "adjacent side:"

       [3sqrt(3)]^2 + x^2 = 6^2, or 9(3) + x^2 = 36, or x^2 = 9, or x = 3.

        

The lengths of the legs of this 30-60-90 triangle are 3 and 3 sqrt(3).

check:  Does 3^2 + [3sqrt(3)]^2 = 6^2?
              Does 9 + 9(3) =              6^2?   YES
8 0
4 years ago
If a substance decays at a rate of 25% every 10 years, how long will it take 512 grams of the substance to decay to 121.5 grams
Juliette [100K]

Answer:

It will take 50 years to decay from 512 grams to 121.5 grams.

Step-by-step explanation:

The decay formula :

N=N_0e^{-\lambda t}

where

N= amount of substance after t time

N₀= initial of substance

t= time.

A substance decays at a rate 25% every 10 years.

So, remaining amount of the substance is = (100%-25%)= 75%

\frac{N}{N_0}=\frac{75\%}{100\%}=\frac{75}{100}=\frac34, t= 10

N=N_0e^{-\lambda t}

\Rightarrow \frac {N}{N_0}=e^{-\lambda t}

\Rightarrow \frac34 =e^{-\lambda .10}

Taking ln both sides

\Rightarrow ln|\frac34| =ln|e^{-\lambda .10}|

\Rightarrow ln|\frac34|=-10\lambda

\Rightarrow \lambda=\frac{ ln|\frac34|}{-10}

Now , N₀= 512 grams, N= 121.5 grams, t=?

N=N_0e^{-\lambda t}

\therefore 121.5=512e^{-\frac{ln|\frac34|}{-10}.t}

\Rightarrow 121.5=512e^{\frac{ln|\frac34|}{10}.t}

\Rightarrow \frac{121.5}{512}=e^{\frac{ln|\frac34|}{10}.t}

Taking ln both sides

\Rightarrow ln|\frac{121.5}{512}|=ln|e^{\frac{ln|\frac34|}{10}.t}|

\Rightarrow ln|\frac{121.5}{512}|={\frac{ln|\frac34|}{10}.t}

\Rightarrow t=\frac{ln|\frac{121.5}{512}|}{\frac{ln|\frac34|}{10}}

\Rightarrow t=\frac{10.ln|\frac{121.5}{512}|}{{ln|\frac34|}}

⇒t=50 years

It will take 50 years to decay from 512 grams to 121.5 grams.

8 0
4 years ago
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