Question

PLEASE FRICKING HELP THIS IS MY LAST QUESTION ON THIS

Answer 1

Answer:   $\bold{y=-65\ \sin\bigg(\dfrac{\pi}{30}x-5\pi\bigg)+80}$

Step-by-step explanation:

y = A sin (Bx - C) + D

• A: amplitude = max - D or  D - min
• B: Period = 2π/B  --->  B = 2π/Period
• C: Phase Shift = C/B   --->     C = B · Phase Shift
• D: center

Given:

D = 80    the field has a height of 160 ft so the center is at y = 80

A = 65    the min is at 5 yds (15 ft). D - min = 80 - 15 = 65

B = 60    the person next to Darla is 10 yds (30 ft) --> Period = 60

              B = 2π/60 = π/30

C = 5π    the field is 300 ft wide so the center is 150 ft

               Phase Shift = 150.   C = B · Phase Shift = π/30 · 150 = 5π

A = (-)      the band ends down (at 15 feet) so A is negative

            $\large\boxed{y=-65\ \sin\bigg(\dfrac{\pi}{30}x-5\pi\bigg)+80}$