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Simora [160]
3 years ago
7

A 30.0 L container was filled by pumping into it 10.0 L of CO2 gas at 60.0 torr of pressure and 20.0 L of O2 gas at 50.0 torr of

pressure. All volumes and pressures were measured at the same temperature. What is the final pressure of CO2 in this mixture?
Chemistry
1 answer:
NeX [460]3 years ago
7 0

The final volume of the Oxygen O2 would simply be equivalent to the overall volume of the final mixture. This is because gases would occupy every space of its container. So in this case, the volume of CO2 and O2 would be the same and it would be 30 L. What would be different is the partial pressures of each.

Answer:

 30 L

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What is the total pressure of three gases, if the partial pressures are: 2.67 mmHg, 45.29 mmHg, and 789.6 mmHg
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Answer:

The total pressure of three gases is 837.56 mmHg.

Explanation:

The pressure exerted by a particular gas in a mixture is known as its partial pressure. So, Dalton's law states that the total pressure of a gas mixture is equal to the sum of the pressures that each gas would exert if it were alone:

PT = PA + PB

This relationship is due to the assumption that there are no attractive forces between the gases.

In this case, the total pressure can be calculated as:

PT= 2.67 mmHg + 45.69 mmHg + 789.6 mmHg

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7 0
3 years ago
A sample of O2 with an initial temperature of 50.0 oC and a volume of 105 L is cooled to -25 oC. The new pressure is 105.4 kPa a
Damm [24]

Answer:

71.92 kPa

Explanation:

Using the combined gas law equation;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (kPa)

P2 = final pressure (kPa)

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

T1 = 50°C = 50 + 273 = 323K

V1 = 105L

T2 = -25°C = -25 + 273 = 248K

P2 = 105.4 kPa

P1 = ?

V2 = 55.0 L

Using P1V1/T1 = P2V2/T2

P1 × 105/323 = 105.4 × 55/248

105P1/323 = 5797/248

0.325P1 = 23.375

P1 = 23.375 ÷ 0.325

P1 = 71.92 kPa

4 0
3 years ago
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