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disa [49]
3 years ago
8

How might a theory relate to a model

Chemistry
1 answer:
oksian1 [2.3K]3 years ago
8 0
These are related but can be independent, because it is possible to, the theories are studied in mathematical logic, especially in model theory
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Determine the number of molecules in a 100. gram sample of CCl4
enyata [817]
100. g CCl4* (1 mol CCl4/ 153.8 g CCl4)* (6.02*10^23 CCl4 molecules/ 1 mol CCl4)= 3.91*10^23 CCl4 molecules.
(Note that the units cancel out so you get the answer)

Hope this helps~
8 0
3 years ago
I need chemistry help text me at (951) 897-8325 PLEASE
user100 [1]
Just post the question on here
7 0
2 years ago
Which equation represents the correct net ionic equation for the reaction between Ca(OH)2 and H2SO4?
Georgia [21]

<u>Answer:</u> The correct net ionic equation for the reaction is 2H^{+}(aq)+2OH^{-}(aq)\rightarrow 2H_2O(l)

<u>Explanation:</u>

Net ionic equation is defined as the equations in which spectator ions are not included.

Spectator ions are the ones that are present equally on the reactant and product sides. They do not participate in the reaction.  

The balanced molecular equation is:

Ca(OH)_2(aq)+H_2SO_4(aq)\rightarrow CaSO_4(aq)+2H_2O(l)

The complete ionic equation follows:

Ca^{2+}(aq)+2OH^-(aq)+2H^+(aq)+SO_4^{2-}(aq)\rightarrow 2Ca^{2+}(aq)+SO_4^{2-}(aq)+H_2O(l)

As calcium and sulfate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

2H^{+}(aq)+2OH^{-}(aq)\rightarrow 2H_2O(l)

Hence, the correct net ionic equation for the reaction is 2H^{+}(aq)+2OH^{-}(aq)\rightarrow 2H_2O(l)

7 0
3 years ago
when 25 ml of 0.12 m aqueous ammonia is titrated with 0.12 m hydrobromic acid, what is the ph at the equivalence point?
maxonik [38]
The pH of solution at equivalence point is 5.2...
5 0
2 years ago
FOR REAL HELPPPPP!!!!
IgorLugansk [536]

Answer:

I belive the answer is gases, liquids, and solids.

Explanation:

The reason I say this is because a vacuum is an empty void of space and time, nothing is there so I believe no sound should be able to penetrate through it.

6 0
3 years ago
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