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olganol [36]
3 years ago
13

How many moles of solute are contained in a 250 ml solution that has a concentration of.85 m?

Chemistry
1 answer:
oksano4ka [1.4K]3 years ago
3 0
Volume = 250 mL in liters : 250 / 1000 => 0.25 L

Molarity = 0.85 M

Number of moles:

n = M x V

n = 0.85 x 0.25

n = 0.21 moles

Choice B
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Answer:

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When Li3PO4 is added, again precipitation takes place.Reaction is:

Co2+(aq) + PO43-(aq)---->Co3(PO4)2(s) ... Precipitate

A. Ca2+ and Co2+ are present in solution

B. Ca2+(aq) + SO42-(aq) ----> CaSO4(s)

C. 3Co2+(aq) + 2PO43-(aq)---->Co3(PO4)2(s)

8 0
3 years ago
An atom or ion has 16 protons, 15 neutrons, and 17 electrons. Is it positive, negative, or
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7 0
2 years ago
How many liters of a 6.0M solution Fe(SCN)2 are needed to prepare 2.0L of a 0.75M solution?
lubasha [3.4K]

Answer:

0.25L

Explanation:

Using the dilution formula

C1V1=C2V2

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V1?

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V2=2.0L

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4 0
3 years ago
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What is the molecular formula of a compound containing 89% cesium (Cs) and 11% oxygen (O) with a molar mass = 298 g/mol?
Maurinko [17]
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M(CsxOy)=298 g/mol
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y=M(CsxOy)w(O)/M(O)
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6 0
3 years ago
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Consider the reaction.
Alex_Xolod [135]

Note the signs of equilibrium:-

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So

if

Concentration of A is 2M then concentration of B should be same .

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\\ \rm\rightarrowtail K=\dfrac{[Products]^a}{[Reactants]^b}

So

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8 0
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