Determina la molaridad y normalidad de la solución NaCl a 30°c

If a reaction occurs, what will be the products of the unbalanced reaction below?Cu(s) + Ni(NO3)2(aq)

Sveta_85 [38]

Answer:

Cu(NO3)2 --> MM187.5558

NiNO3 *COEF2* --> 120.6983

3 0

4 years ago

What’s the PH and OH- of 6.0 x 10^-10?

Zarrin [17]

Answer:

The answer to your question is pH = 9.2; [OH] = 1.58 x 10⁻⁵

Explanation:

Data

[H⁺] = 6.0 x 10⁻¹⁰ M

pH = ?

pH definition. pH measures the hydrogen concentration. pH measures the acidity and the alkalinity of a solution. A solution is acid if the pH goes from 0 to 6.9, a neutral solution has a pH of 7 and an alkali solution has a pH from 7.1 to 14.

pOH measures the [OH⁻] concentration

Formula

pH = -log[H⁺]

pH + pOH = 14

-Substitution

pH = -log[6 x 10⁻¹⁰]

-Simplification

pH = - (-9.2)

pH = 9.2

-Calculate pOH

pOH = 14 - pH

pOH = 14 - 9.2

pOH = 4.8

-Calculate the concentration of OH⁻

pOH = -log[OH⁻]

[OH⁻] = -antilog4.8

[OH] = 1.58 x 10⁻⁵

8 0

3 years ago

Which trends are observed as each of the elements within Group 15 on the Periodic Table is considered in order from top to botto

aniked [119]

4) their metallic properties increase and their atomic radii increase.

5 0

3 years ago

Read 2 more answers

Which evidence indicates the ocean plays a large role in climate change?

Elza [17]

You already gave the answer

5 0

3 years ago

6. Calculate the new pressure in atm if 2.45 L of a gas at a pressure of 1.20 atm is contracted to a new

alukav5142 [94]

Answer:

$\boxed {\boxed {\sf x \approx 1.34 \ atm}}$

Explanation:

Since we are dealing with temperature and pressure, we must use Boyle's Law. This states that the pressure is inversely proportional to the volume. The formula is:

$P_1V_1=P_2V_2$

Where P is the pressure and V is the volume.

We know the original pressure (P₁) of the gas is 1.20 atmospheres and the volume (V₁) is 2.45 liters.

$1.20 \ atm * 2.45 \ L = P_2V_2$

We also know the gas is contracted to a new volume of 2.20 liters (V₂) , but we do not know the pressure (P₂). We can use x.

$1.20 \ atm *2.45 \ L = x * 2.20 \ L$

We can solve the left side of the equation and multiply.

$2.94 \ atm *L= x*2.20 \ L$

We are trying to find the new pressure (x), so we must isolate the variable. It is being multiplied by 2.20 liters. The inverse of multiplication is division, so we divide both sides by 2.20 L.

$\frac {2.94 \ atm *L}{2.20 \ L}=\frac{x*2.20 \ L}{2.20 \ L}$